Question

based on the spinner shown, what is the probability of the next spin landing on an even number? options: \\(\frac{1}{2}\\), \\(\frac{7}{10}\\), \\(\frac{3}{5}\\), \\(\frac{2}{5}\\)

Explanation:

Step1: Count total sections

The spinner has 10 equal - sized sections (by counting all the numbered regions: 1, 2, 2, 3, 3, 3, 4, 4, 4, 4? Wait, no, let's count again. Looking at the spinner: 1 (1 section), 2 (2 sections), 3 (3 sections), 4 (4 sections). Wait, 1 + 2+3 + 4=10. So total number of sections $n = 10$.

Step2: Count even - numbered sections

Even numbers on the spinner are 2 and 4. The number of 2s is 2, and the number of 4s is 4. So the total number of even - numbered sections $m=2 + 4=6$.

Step3: Calculate probability

The probability $P$ of an event is given by the formula $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. Here, the favorable outcomes are landing on an even number, so $P=\frac{m}{n}=\frac{6}{10}=\frac{3}{5}$.

Answer:

$\frac{3}{5}$ (corresponding to the option $\frac{3}{5}$)