Question

bob estimates that he weighs 170 pounds, but he actually weighs 148 pounds. what is the percent error in bobs estimate? ?% round to the nearest whole percent.

Explanation:

Step1: Find the absolute error

The absolute error is the absolute value of the difference between the estimated value and the actual value. So, we calculate $|170 - 148|$.
$|170 - 148| = |22| = 22$

Step2: Calculate the percent error

The formula for percent error is $\frac{\text{Absolute Error}}{\text{Actual Value}} \times 100\%$. We substitute the absolute error (22) and the actual value (148) into the formula.
$\frac{22}{148} \times 100\% \approx 0.1486 \times 100\% = 14.86\%$

Step3: Round to the nearest whole percent

Rounding 14.86% to the nearest whole percent gives 15%.

Answer:

15