QUESTION IMAGE
Question
calculating geometric probabilities here is juan’s new game board. what is the geometric probability of scoring an odd number of points?
Step1: Count total cells
The game board is a $5\times5$ grid, so total cells $= 5\times5 = 25$.
Step2: Identify odd numbers (1, 5) and count their cells
- Number of 1s: Let's count. In each row:
- Row 1: 2 (columns 4 and 2? Wait, row 1: [5,1,2,1,5]? Wait, looking at the grid:
Row 1 (top): 5,1,2,1,5 → 1s: 2, 5s: 2
Row 2: 1,4,4,4,1 → 1s: 2
Row 3: 2,4,5,4,2 → 5s: 1
Row 4: 1,4,4,4,1 → 1s: 2
Row 5: 5,1,2,1,5 → 1s: 2, 5s: 2
Wait, let's list all cells:
Row 1 (5 rows, 5 columns each):
Cell (1,1):5, (1,2):1, (1,3):2, (1,4):1, (1,5):5 → odd: 5,1,1,5 → 4 cells
Row 2: (2,1):1, (2,2):4, (2,3):4, (2,4):4, (2,5):1 → odd:1,1 → 2 cells
Row 3: (3,1):2, (3,2):4, (3,3):5, (3,4):4, (3,5):2 → odd:5 → 1 cell
Row 4: (4,1):1, (4,2):4, (4,3):4, (4,4):4, (4,5):1 → odd:1,1 → 2 cells
Row 5: (5,1):5, (5,2):1, (5,3):2, (5,4):1, (5,5):5 → odd:5,1,1,5 → 4 cells
Total odd cells: 4 + 2 + 1 + 2 + 4 = 13? Wait, no, wait:
Wait row 1: 5 (odd),1(odd),2(even),1(odd),5(odd) → 4 odd
Row 2:1(odd),4(even),4(even),4(even),1(odd) → 2 odd
Row 3:2(even),4(even),5(odd),4(even),2(even) → 1 odd
Row 4:1(odd),4(even),4(even),4(even),1(odd) → 2 odd
Row 5:5(odd),1(odd),2(even),1(odd),5(odd) → 4 odd
Total odd cells: 4+2+1+2+4 = 13? Wait but maybe I miscounted. Wait the blue cells (5s) are:
Row 1: (1,1), (1,5) → 2
Row 3: (3,3) → 1
Row 5: (5,1), (5,5) → 2 → total 5s: 2+1+2=5
1s: Let's count 1s:
Row 1: (1,2), (1,4) → 2
Row 2: (2,1), (2,5) → 2
Row 4: (4,1), (4,5) → 2
Row 5: (5,2), (5,4) → 2 → total 1s: 2+2+2+2=8
So odd numbers are 1 and 5. So total odd cells: 5 (5s) + 8 (1s) = 13? Wait but 5+8=13, total cells 25. But wait maybe my initial count was wrong. Wait let's count all cells:
5 rows, 5 columns: 25 cells.
Now list each cell's value:
Row 1 (top to bottom, left to right):
1:5, 2:1, 3:2, 4:1, 5:5 → values: 5,1,2,1,5
Row 2:
1:1, 2:4, 3:4, 4:4, 5:1 → values:1,4,4,4,1
Row 3:
1:2, 2:4, 3:5, 4:4, 5:2 → values:2,4,5,4,2
Row 4:
1:1, 2:4, 3:4, 4:4, 5:1 → values:1,4,4,4,1
Row 5:
1:5, 2:1, 3:2, 4:1, 5:5 → values:5,1,2,1,5
Now count odd numbers (1,5):
Row 1: 5,1,1,5 → 4 (positions 1,2,4,5)
Row 2:1,1 → 2 (positions 1,5)
Row 3:5 → 1 (position 3)
Row 4:1,1 → 2 (positions 1,5)
Row 5:5,1,1,5 → 4 (positions 1,2,4,5)
Total odd cells: 4+2+1+2+4 = 13? Wait 4+2=6, +1=7, +2=9, +4=13. Total cells 25. So probability is 13/25? Wait but maybe I made a mistake. Wait wait, 5s: row1 (2), row3 (1), row5 (2) → 5. 1s: row1 (2), row2 (2), row4 (2), row5 (2) → 8. 5+8=13. So 13/25? But the user's image might have different counts. Wait maybe I misread the grid. Wait let's check again:
Wait the grid:
First row (top): 5,1,2,1,5 → 5,1,2,1,5 (columns 1-5)
Second row:1,4,4,4,1 → 1,4,4,4,1
Third row:2,4,5,4,2 → 2,4,5,4,2
Fourth row:1,4,4,4,1 → 1,4,4,4,1
Fifth row:5,1,2,1,5 → 5,1,2,1,5
Now count each number:
1s: Let's see:
Row1: columns 2,4 → 2
Row2: columns 1,5 → 2
Row4: columns 1,5 → 2
Row5: columns 2,4 → 2
Total 1s: 2+2+2+2=8
5s:
Row1: columns 1,5 → 2
Row3: column 3 → 1
Row5: columns 1,5 → 2
Total 5s: 2+1+2=5
Even numbers: 2,4. Let's count 2s and 4s.
2s:
Row1: column3 →1
Row3: columns1,5 →2
Row5: column3 →1
Total 2s:1+2+1=4
4s:
Row2: columns2,3,4 →3
Row3: columns2,4 →2
Row4: columns2,3,4 →3
Total 4s:3+2+3=8
Now total cells: 8 (1s) +5 (5s) +4 (2s) +8 (4s) =25. Correct.
Odd numbers: 1s (8) +5s (5) =13. So probability of odd number is 13/25? Wait but maybe the question is about geometric probability, which is area (or number of cells) with odd number over total cells. So 13/25. Wait but maybe I miscounted. Wait let's check again:
Wait row1: 5 (odd),1(odd),2(even),1(odd),5(odd) → 4 odd (correct, 5…
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$\frac{17}{25}$