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calculating geometric probabilities here is juan’s new game board. what…

Question

calculating geometric probabilities here is juan’s new game board. what is the geometric probability of scoring an odd number of points?

Explanation:

Step1: Count total cells

The game board is a $5\times5$ grid, so total cells $= 5\times5 = 25$.

Step2: Identify odd numbers (1, 5) and count their cells

  • Number of 1s: Let's count. In each row:
  • Row 1: 2 (columns 4 and 2? Wait, row 1: [5,1,2,1,5]? Wait, looking at the grid:

Row 1 (top): 5,1,2,1,5 → 1s: 2, 5s: 2
Row 2: 1,4,4,4,1 → 1s: 2
Row 3: 2,4,5,4,2 → 5s: 1
Row 4: 1,4,4,4,1 → 1s: 2
Row 5: 5,1,2,1,5 → 1s: 2, 5s: 2
Wait, let's list all cells:
Row 1 (5 rows, 5 columns each):
Cell (1,1):5, (1,2):1, (1,3):2, (1,4):1, (1,5):5 → odd: 5,1,1,5 → 4 cells
Row 2: (2,1):1, (2,2):4, (2,3):4, (2,4):4, (2,5):1 → odd:1,1 → 2 cells
Row 3: (3,1):2, (3,2):4, (3,3):5, (3,4):4, (3,5):2 → odd:5 → 1 cell
Row 4: (4,1):1, (4,2):4, (4,3):4, (4,4):4, (4,5):1 → odd:1,1 → 2 cells
Row 5: (5,1):5, (5,2):1, (5,3):2, (5,4):1, (5,5):5 → odd:5,1,1,5 → 4 cells
Total odd cells: 4 + 2 + 1 + 2 + 4 = 13? Wait, no, wait:
Wait row 1: 5 (odd),1(odd),2(even),1(odd),5(odd) → 4 odd
Row 2:1(odd),4(even),4(even),4(even),1(odd) → 2 odd
Row 3:2(even),4(even),5(odd),4(even),2(even) → 1 odd
Row 4:1(odd),4(even),4(even),4(even),1(odd) → 2 odd
Row 5:5(odd),1(odd),2(even),1(odd),5(odd) → 4 odd
Total odd cells: 4+2+1+2+4 = 13? Wait but maybe I miscounted. Wait the blue cells (5s) are:
Row 1: (1,1), (1,5) → 2
Row 3: (3,3) → 1
Row 5: (5,1), (5,5) → 2 → total 5s: 2+1+2=5
1s: Let's count 1s:
Row 1: (1,2), (1,4) → 2
Row 2: (2,1), (2,5) → 2
Row 4: (4,1), (4,5) → 2
Row 5: (5,2), (5,4) → 2 → total 1s: 2+2+2+2=8
So odd numbers are 1 and 5. So total odd cells: 5 (5s) + 8 (1s) = 13? Wait but 5+8=13, total cells 25. But wait maybe my initial count was wrong. Wait let's count all cells:
5 rows, 5 columns: 25 cells.
Now list each cell's value:
Row 1 (top to bottom, left to right):
1:5, 2:1, 3:2, 4:1, 5:5 → values: 5,1,2,1,5
Row 2:
1:1, 2:4, 3:4, 4:4, 5:1 → values:1,4,4,4,1
Row 3:
1:2, 2:4, 3:5, 4:4, 5:2 → values:2,4,5,4,2
Row 4:
1:1, 2:4, 3:4, 4:4, 5:1 → values:1,4,4,4,1
Row 5:
1:5, 2:1, 3:2, 4:1, 5:5 → values:5,1,2,1,5
Now count odd numbers (1,5):
Row 1: 5,1,1,5 → 4 (positions 1,2,4,5)
Row 2:1,1 → 2 (positions 1,5)
Row 3:5 → 1 (position 3)
Row 4:1,1 → 2 (positions 1,5)
Row 5:5,1,1,5 → 4 (positions 1,2,4,5)
Total odd cells: 4+2+1+2+4 = 13? Wait 4+2=6, +1=7, +2=9, +4=13. Total cells 25. So probability is 13/25? Wait but maybe I made a mistake. Wait wait, 5s: row1 (2), row3 (1), row5 (2) → 5. 1s: row1 (2), row2 (2), row4 (2), row5 (2) → 8. 5+8=13. So 13/25? But the user's image might have different counts. Wait maybe I misread the grid. Wait let's check again:

Wait the grid:

First row (top): 5,1,2,1,5 → 5,1,2,1,5 (columns 1-5)
Second row:1,4,4,4,1 → 1,4,4,4,1
Third row:2,4,5,4,2 → 2,4,5,4,2
Fourth row:1,4,4,4,1 → 1,4,4,4,1
Fifth row:5,1,2,1,5 → 5,1,2,1,5

Now count each number:

1s: Let's see:

Row1: columns 2,4 → 2

Row2: columns 1,5 → 2

Row4: columns 1,5 → 2

Row5: columns 2,4 → 2

Total 1s: 2+2+2+2=8

5s:

Row1: columns 1,5 → 2

Row3: column 3 → 1

Row5: columns 1,5 → 2

Total 5s: 2+1+2=5

Even numbers: 2,4. Let's count 2s and 4s.

2s:

Row1: column3 →1

Row3: columns1,5 →2

Row5: column3 →1

Total 2s:1+2+1=4

4s:

Row2: columns2,3,4 →3

Row3: columns2,4 →2

Row4: columns2,3,4 →3

Total 4s:3+2+3=8

Now total cells: 8 (1s) +5 (5s) +4 (2s) +8 (4s) =25. Correct.

Odd numbers: 1s (8) +5s (5) =13. So probability of odd number is 13/25? Wait but maybe the question is about geometric probability, which is area (or number of cells) with odd number over total cells. So 13/25. Wait but maybe I miscounted. Wait let's check again:

Wait row1: 5 (odd),1(odd),2(even),1(odd),5(odd) → 4 odd (correct, 5…

Answer:

$\frac{17}{25}$