Question

caule folha
4
5 8
6 3
7 2 5
8 7 8
9 0 1 6 9
10 2
11
12 5
13 0 4 6
14 2
15 0 7
16

preencha os números que faltam.

pesos dos cães
peso (lbs ) | número de cães
41-60 |
61-80 |
81-100 | 6
101-120 | 1
121-140 | 4
141-160 | 3

Explanation:

Step1: Analyze 41 - 60 (Caule 4,5,6)

Caule 4: 0 (assumed, since no folha), Caule 5: 8 (one number), Caule 6: 3 (one number). Wait, actually, the stem - leaf plot: Caule (stem) and Folha (leaf). So for weight range, we need to map stem (tens place) and leaf (units place) to the weight. Let's clarify:

Wait, maybe the stem is the tens digit? Wait, the first table: Caule (stem) and Folha (leaf). Let's list all data points:

- Caule 4: no leaf? Wait, maybe I misread. Wait, the first table:

Caule 4: (no leaf? Or maybe 4 is tens, so 40 + leaf, but leaf is missing? Wait, no, let's check the numbers:

Wait, maybe the stem is the tens digit, so:

Caule 4: weight 40 + leaf, but leaf is empty? No, maybe the first table is a stem - leaf plot where Caule is stem (tens) and Folha is leaf (units). Let's list all weights:

- Caule 4: no leaf? Wait, no, the first row: Caule 4, Folha (empty). Then Caule 5, Folha 8: 58
- Caule 6, Folha 3: 63
- Caule 7, Folha 2,5: 72,75
- Caule 8, Folha 7,8: 87,88
- Caule 9, Folha 0,1,6,9: 90,91,96,99
- Caule 10, Folha 2: 102
- Caule 11: no leaf
- Caule 12, Folha 5: 125
- Caule 13, Folha 0,4,6: 130,134,136
- Caule 14, Folha 2: 142
- Caule 15, Folha 0,7: 150,157
- Caule 16: no leaf

Now, let's categorize each weight into the ranges:

1. 41 - 60: Weights between 41 and 60 (inclusive). Let's see:

- 58 (Caule 5, Folha 8): 58 is in 41 - 60? Wait, 41 - 60: 41 to 60. So 58 is in, 63 is in 61 - 80. Wait, 58: 58 is between 41 - 60. Then Caule 4: no weight? Wait, maybe I made a mistake. Wait, maybe the stem is the tens digit, so Caule 4: 40 + leaf, but leaf is empty. So no weight. Caule 5: 50 + 8 = 58. Caule 6: 60 + 3 = 63. So 58 is in 41 - 60, and is there another? Wait, maybe I misread the stem - leaf. Wait, maybe the stem is the tens, so:

Caule 4: 40 - 49: leaf would be 0 - 9, but no leaf, so 0 numbers? No, that can't be. Wait, the first table:

Wait, the first column is Caule (stem), second is Folha (leaf). Let's count the number of leaves for each stem, but we need to map to the weight ranges.

Wait, the second table is "Pesos dos cães" (Weights of dogs) with ranges: 41 - 60, 61 - 80, 81 - 100, 101 - 120, 121 - 140, 141 - 160.

Let's list all weights from the stem - leaf:

- Caule 4: no leaf → 0 weights
- Caule 5: leaf 8 → 58
- Caule 6: leaf 3 → 63
- Caule 7: leaves 2,5 → 72,75
- Caule 8: leaves 7,8 → 87,88
- Caule 9: leaves 0,1,6,9 → 90,91,96,99
- Caule 10: leaf 2 → 102
- Caule 11: no leaf → 0
- Caule 12: leaf 5 → 125
- Caule 13: leaves 0,4,6 → 130,134,136
- Caule 14: leaf 2 → 142
- Caule 15: leaves 0,7 → 150,157
- Caule 16: no leaf → 0

Now, categorize each weight:

- 41 - 60: Weights ≥41 and ≤60. The only weight here is 58 (from Caule 5, leaf 8). Wait, is there another? Caule 4: no weight. So 1 number? Wait, no, maybe I messed up the stem. Maybe the stem is the tens, so Caule 4: 40 - 49, so weights 40 + leaf. But leaf is empty, so no. Caule 5: 50 - 59, leaf 8 → 58. Caule 6: 60 - 69, leaf 3 → 63. So 58 is in 41 - 60? Wait, 41 - 60: 41 to 60. 58 is between 41 and 60, yes. So 1 number? But that seems low. Wait, maybe the stem is the units? No, that doesn't make sense. Wait, maybe the first table is a stem - leaf for two - digit numbers, where Caule is the tens and Folha is the units. Let's re - check:

Wait, the problem says "Preencha os números que faltam" (Fill in the missing numbers). The second table has columns "Peso (Lbs)" (Weight in pounds) and "Número de cães" (Number of dogs).

Let's list all the weights from the stem - leaf plot:

- Caule 5: 58
- Caule 6: 63
- Caule 7: 72, 75
- Caule 8: 87, 88
- Caule 9: 90, 91, 96, 99
- Caule 10: 102
- Caule 12: 125
- Caule 13: 130, 134, 136
- Caule 14: 142
- Caule 15: 150, 157

Now, let's count how many are in each range:

1. 41 - 60: Weights between 41 and 60. The only one is 58. Wait, but maybe I missed Caule 4? If Caule 4 has a leaf, but it's empty. Maybe the first row (Caule 4) has no leaf, so 0. So 1? But that seems wrong. Wait, maybe the stem is the tens, so Caule 4: 40 - 49, so weights 40 + leaf. If leaf is empty, 0. Caule 5: 50 - 59, leaf 8 → 58 (1). Caule 6: 60 - 69, leaf 3 → 63 (which is in 61 - 80). So 41 - 60: 1?

2. 61 - 80: Weights between 61 and 80. Let's see:

- 63 (Caule 6, leaf 3)
- 72 (Caule 7, leaf 2)
- 75 (Caule 7, leaf 5)

So that's 3 numbers (63,72,75).

Wait, let's verify:

- 63: 61 - 80: yes (63 is between 61 and 80)
- 72: yes
- 75: yes

So 3 numbers.

Now, let's check the other ranges to confirm:

- 81 - 100: 87,88,90,91,96,99 → 6 numbers (matches the table)
- 101 - 120: 102 → 1 number (matches)
- 121 - 140: 125,130,134,136 → 4 numbers (matches)
- 141 - 160: 142,150,157 → 3 numbers (matches)

So for 41 - 60: only 58, so 1? Wait, but maybe I made a mistake with Caule 4. If Caule 4 has a leaf, but it's not shown. Wait, the first table: Caule 4, Folha (empty). So no weight. So 41 - 60: 1 dog.

61 - 80: 63,72,75 → 3 dogs.

Step1: Count 41 - 60

Weights in 41 - 60: 58 (from Caule 5, Folha 8). So count = 1.

Step2: Count 61 - 80

Weights in 61 - 80: 63 (Caule 6, Folha 3), 72 (Caule 7, Folha 2), 75 (Caule 7, Folha 5). So count = 3.

Answer:

For 41 - 60: 1
For 61 - 80: 3