Question

at a certain company, the mentoring program and the community outreach program meet at the same time, so it is impossible for an employee to do both. if the probability that an employee participates in the mentoring program is 0.34, and the probability that an employee participates in the outreach program is 0.49, what is the probability that an employee does the mentoring program or the community outreach program? provide your answer below.

Explanation:

Step1: Identify mutually exclusive events

Since an employee can't do both programs, the events are mutually exclusive. The formula for the probability of the union of two mutually exclusive events \( P(A \cup B) \) is \( P(A) + P(B) \).

Step2: Apply the formula

Let \( A \) be the event of participating in the mentoring program (\( P(A) = 0.34 \)) and \( B \) be the event of participating in the outreach program (\( P(B) = 0.49 \)). Then \( P(A \cup B)=P(A)+P(B)=0.34 + 0.49 \).

Step3: Calculate the result

\( 0.34+0.49 = 0.83 \).

Answer:

\( 0.83 \)