Question

ch 12* here is the probability model for the political affiliation of a randomly chosen adult in the united states.
political affiliation republican independent democrat other
probability 0.25 0.42 0.30?
the probability that a randomly chosen american adults political affiliation is \other\ must be
any number between 0 and 1.
0.00.
0.30.
0.03.
question 12 1 pts
ch 12 a candy company manufactures bags of colorful candies. the company reports that it makes 10% each of green and red candies and 20% each of yellow, blue, and orange candies. the rest of the candies are brown.
if you pick a candy at random, what is the probability that it is brown?
0.40
0.10
0.20
0.30

Explanation:

Step1: Recall probability rule

The sum of probabilities of all possible outcomes in a probability - model is 1.

Step2: Calculate probability of 'Other' for political affiliation

Let \(P(\text{Other})\) be the probability of the 'Other' political affiliation. We know that \(P(\text{Republican}) = 0.25\), \(P(\text{Independent})=0.42\), \(P(\text{Democrat}) = 0.30\). Then \(P(\text{Other})=1-(0.25 + 0.42+0.30)=1 - 0.97 = 0.03\).

Step3: Calculate probability of brown candy

Let \(P(\text{Brown})\) be the probability of picking a brown candy. We know that \(P(\text{Green})=0.10\), \(P(\text{Red}) = 0.10\), \(P(\text{Yellow})=0.20\), \(P(\text{Blue}) = 0.20\), \(P(\text{Orange})=0.20\). Then \(P(\text{Brown})=1-(0.10 + 0.10+0.20 + 0.20+0.20)=1 - 0.80=0.20\).

Answer:

For the political - affiliation problem: 0.03
For the candy - color problem: 0.20