Question

challenge suppose you have a bag with 20 letter tiles in it and 9 of the tiles are the letter c. if you pick a letter tile at random from the bag, the probability that it is the letter c is \\(\frac{9}{20}\\). suppose another bag has 500 letter tiles in it and 170 of the tiles are the letter c. write the probability of picking a tile that is the letter c as a fraction and as a percent. from which bag are you more likely to pick a tile that is the letter c?\\(p(c)\\) as a fraction is \\(\square\\). (simplify your answer.)

Explanation:

Step1: Simplify the fraction

$\frac{170}{500} = \frac{170\div10}{500\div10} = \frac{17}{50}$

Step2: Convert fraction to percent

$\frac{17}{50} \times 100\% = 34\%$

Step3: Compare first bag's percent

$\frac{9}{20} \times 100\% = 45\%$

Step4: Compare probabilities

$34\% < 45\%$, so first bag has higher probability

Answer:

• P(C) as a fraction: $\frac{17}{50}$
• P(C) as a percent: $34\%$
• More likely bag: The second bag with 500 tiles