Question

check for understanding
a soccer team finished their season in which they won 18 times, lost 4 times, and tied 3 times. what is the probability that they didn’t lose a game?

Explanation:

Step1: Calculate total games

The total number of games is the sum of wins, losses and ties. So, $18 + 4+3=25$ games.

Step2: Calculate non - loss games

The number of non - loss games is the sum of wins and ties. So, $18 + 3=21$ games.

Step3: Calculate probability

The probability $P$ of not losing a game is the number of non - loss games divided by the total number of games. So, $P=\frac{21}{25}$.

Answer:

$\frac{21}{25}$