Question

the chicago bulls, led by michael jordan, had one of the greatest nba dynasties of all time. they won a total of 6 nba championships between 1991 and 1998. during the 1992 - 1993 season, the chicago bulls beat the phoenix suns in 6 games to become nba champions. michael jordan scored 246 points total during those 6 games and the number of points he scored each game can be found below.
michael jordan points in 1993 nba finals

michael jordan points	number of points (frequency)
game 2	41
game 3	55
game 4	44
game 5	42
game 6	31

of all the points michael jordan scored in the 1993 nba finals, what percentage of them did he score in game 6? (make sure to round your answer to 2 decimal places, so if you thought the answer was 65.4321% you would type in 65.43% as your answer).

Explanation:

Step1: Identify points in Game 6 and total points

Points in Game 6: \( 31 \)
Total points: \( 246 \)

Step2: Calculate the percentage

Percentage formula: \( \frac{\text{Points in Game 6}}{\text{Total Points}} \times 100 \)
Substitute values: \( \frac{31}{246} \times 100 \)
Calculate \( \frac{31}{246} \approx 0.126016 \)
Multiply by 100: \( 0.126016 \times 100 = 12.6016\% \)

Step3: Round to two decimal places

\( 12.6016\% \approx 12.60\% \)

Answer:

12.60%