creating a protein
copy one side of dna strand and then transcribe it to rna. mrna goes from the nucleus to the cytoplasm and then to the ribosome. mrna goes through ribosome 3 bases at a time. trna matches up with the open dna bases. trna releases the amino acid at the top, which joins the chain of amino acids being produced
making a protein:
atg gta gct = uac ______ →tyrosine, ______, ______

Question

Accepted Answer

To solve the problem of matching the DNA sequence to mRNA, tRNA, and the resulting amino acid, we follow these steps:

### Step 1: Transcribe DNA to mRNA
The DNA sequence given is $ \text{ATG GTA GCT} $. During transcription, DNA is converted to mRNA, where:
- $ \text{A} $ (Adenine) pairs with $ \text{U} $ (Uracil) in RNA,
- $ \text{T} $ (Thymine) pairs with $ \text{A} $ (Adenine) in RNA,
- $ \text{G} $ (Guanine) pairs with $ \text{C} $ (Cytosine) in RNA,
- $ \text{C} $ (Cytosine) pairs with $ \text{G} $ (Guanine) in RNA.

Let's transcribe each codon:
- For $ \text{ATG} $: $ \text{A}
ightarrow \text{U} $, $ \text{T}
ightarrow \text{A} $, $ \text{G}
ightarrow \text{C} $, so $ \text{ATG}
ightarrow \text{UAC} $
- For $ \text{GTA} $: $ \text{G}
ightarrow \text{C} $, $ \text{T}
ightarrow \text{A} $, $ \text{A}
ightarrow \text{U} $, so $ \text{GTA}
ightarrow \text{CAU} $
- For $ \text{GCT} $: $ \text{G}
ightarrow \text{C} $, $ \text{C}
ightarrow \text{G} $, $ \text{T}
ightarrow \text{A} $, so $ \text{GCT}
ightarrow \text{CGA} $

### Step 2: Determine tRNA from mRNA
tRNA is complementary to mRNA. Let's find tRNA for each mRNA codon:
- For $ \text{UAC} $ (mRNA): $ \text{U}
ightarrow \text{A} $, $ \text{A}
ightarrow \text{U} $, $ \text{C}
ightarrow \text{G} $, so tRNA is $ \text{AUG} $
- For $ \text{CAU} $ (mRNA): $ \text{C}
ightarrow \text{G} $, $ \text{A}
ightarrow \text{U} $, $ \text{U}
ightarrow \text{A} $, so tRNA is $ \text{GUA} $
- For $ \text{CGA} $ (mRNA): $ \text{C}
ightarrow \text{G} $, $ \text{G}
ightarrow \text{C} $, $ \text{A}
ightarrow \text{U} $, so tRNA is $ \text{GCU} $

### Step 3: Find Amino Acids from mRNA Codons
Using the genetic code table:
- $ \text{UAC} $ codes for Tyrosine (as given, but let's confirm the others too for completeness, though the problem focuses on the first part). Wait, the problem has "ATG GTA GCT = UAC ______ ______ → Tyrosine, ______ ______". Wait, maybe we need to transcribe DNA to mRNA first. Wait, the DNA sequence is ATG GTA GCT. Let's transcribe DNA (template strand? Wait, DNA to mRNA: DNA has T, mRNA has U. So DNA (coding strand) ATG GTA GCT would have mRNA as UAC CAU CGA (since A→U, T→A, G→C, C→G). Then tRNA is complementary to mRNA: AUG GUA GCU. Now, the amino acid for UAC (mRNA) is Tyrosine (as per the problem's hint). Wait, maybe the blanks are for the other mRNA codons and their tRNAs or amino acids. Wait, the problem says "ATG GTA GCT = UAC ______ ______ → Tyrosine, ______ ______". Let's re-express:

DNA: ATG (codon 1), GTA (codon 2), GCT (codon 3)

mRNA from DNA: A (DNA)→U (mRNA), T→A, G→C, C→G. So:

- ATG (DNA) → UAC (mRNA)
- GTA (DNA) → CAU (mRNA)
- GCT (DNA) → CGA (mRNA)

Then tRNA for mRNA:

- UAC (mRNA) → AUG (tRNA)
- CAU (mRNA) → GUA (tRNA)
- CGA (mRNA) → GCU (tRNA)

Amino acids:

- UAC (mRNA) → Tyrosine (Tyr)
- CAU (mRNA) → Histidine (His)
- CGA (mRNA) → Arginine (Arg)

But the problem's format is "ATG GTA GCT = UAC ______ ______ → Tyrosine, ______ ______". So filling the blanks:

ATG GTA GCT = UAC **CAU** **CGA** → Tyrosine, **Histidine** **Arginine** (or tRNAs: AUG, GUA, GCU, but the problem might be about mRNA codons and amino acids). Wait, maybe the first blank after UAC is the next mRNA codon (CAU), then CGA, then the amino acids after Tyrosine. But the problem says "→ Tyrosine, ______ ______". Wait, maybe the DNA is being transcribed to mRNA, then tRNA, then amino acid. Let's focus on the given: "ATG GTA GCT = UAC ______ ______ → Tyrosine, ______ ______".

Wait, the first part: DNA ATG → mRNA UAC (since A→U, T→A, G→C, C→G). Then GTA (DNA) → CAU (mRNA), GCT (DNA) → CGA (mRNA). So the mRNA sequence is UAC CAU CGA. Then tRNA is AUG GUA GCU. Amino acids: UAC→Tyr, CAU→His, CGA→Arg.

So the blanks would be:

ATG GTA GCT = UAC, **CAU**, **CGA** → Tyrosine, **Histidine**, **Arginine** (or tRNAs: AUG, GUA, GCU, but the problem's arrow is to Tyrosine, so maybe the next amino acids).

But the problem might be simpler: transcribe DNA to mRNA (ATG→UAC, GTA→CAU, GCT→CGA), then tRNA (UAC→AUG, CAU→GUA, CGA→GCU), then amino acids (UAC→Tyr, CAU→His, CGA→Arg).

So the answer for the blanks (assuming the format is mRNA codons and then tRNAs or amino acids) would be:

ATG GTA GCT = UAC, CAU, CGA → Tyrosine, Histidine, Arginine (or tRNAs: AUG, GUA, GCU). But the problem's given is "→ Tyrosine, ______ ______", so maybe the first mRNA codon is UAC (Tyrosine), then the next two mRNA codons are CAU and CGA, with their amino acids His and Arg.

But let's check the initial problem again: "ATG GTA GCT = UAC ______ ______ → Tyrosine, ______ ______". So the first blank after UAC is the next mRNA codon (CAU), then the next (CGA), then the amino acids after Tyrosine (His, Arg).

So the filled blanks would be:

ATG GTA GCT = UAC, CAU, CGA → Tyrosine, Histidine, Arginine

(Or if tRNAs, then AUG, GUA, GCU, but the problem's arrow is to Tyrosine, so amino acids are more likely.)

# Answer:
ATG GTA GCT = UAC, CAU, CGA → Tyrosine, Histidine, Arginine

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QUESTION IMAGE

Question

Explanation:

Step 1: Transcribe DNA to mRNA

Step 2: Determine tRNA from mRNA

Step 3: Find Amino Acids from mRNA Codons

Answer: