Question

determine the possible weight of the maine coon. choose the correct answer and explanation.
a) $x \geq 14\frac{3}{4}$: the weight of the maine coon is at least $14\frac{3}{4}$ pounds.
b) $x \geq 14\frac{3}{4}$: the weight of the maine coon is more than $14\frac{3}{4}$ pounds.
c) $x \leq 14\frac{3}{4}$: the weight of the maine coon is at most $14\frac{3}{4}$ pounds.
d) $x \leq 14\frac{3}{4}$: the weight of the maine coon is less than $14\frac{3}{4}$ pounds.

Explanation:

To determine the correct option, we analyze the inequality symbols:

• For option A: \( x \geq 14\frac{3}{4} \) means \( x \) is greater than or equal to \( 14\frac{3}{4} \), which translates to "the weight is at least \( 14\frac{3}{4} \) pounds" (since "at least" implies the value is the minimum, and it can be equal or more).
• Option B: \( x \geq 14\frac{3}{4} \) does not mean "more than" (which would be \( x > 14\frac{3}{4} \), strict inequality).
• Option C: \( x \leq 14\frac{3}{4} \) means "at most" (maximum value), but the symbol here in C is written with a typo (same as A's inequality but description is wrong). Wait, no, looking at the options:

Wait, re - examining:
Option A: \( x\geq14\frac{3}{4} \), description "at least" (correct, as \( \geq \) means greater than or equal to, so minimum is \( 14\frac{3}{4} \), can be equal or more).
Option B: \( x\geq14\frac{3}{4} \) but description "more than" (wrong, "more than" is \( > \), not \( \geq \)).
Option C: \( x\leq14\frac{3}{4} \) (description "at most" would be correct for \( \leq \), but the inequality here in C is written as \( x\leq14\frac{3}{4} \)? Wait, the original options:
Wait the user's image:
Option A: \( x\geq14\frac{3}{4} \): The weight of the Maine Coon is at least \( 14\frac{3}{4} \) pounds.
Option B: \( x\geq14\frac{3}{4} \): The weight of the Maine Coon is more than \( 14\frac{3}{4} \) pounds. (Wrong, because \( \geq \) includes equality)
Option C: \( x\leq14\frac{3}{4} \): The weight of the Maine Coon is at most \( 14\frac{3}{4} \) pounds. (But the inequality here in C is \( x\leq14\frac{3}{4} \), but the first part of the option says \( x\leq14\frac{3}{4} \)? Wait, maybe a typo in the original, but focusing on A:
"At least" means the value is the lower bound, so \( x \) can be equal to or greater than \( 14\frac{3}{4} \), which is exactly what \( x\geq14\frac{3}{4} \) means.

Answer:

A. \( x \geq 14\frac{3}{4} \): The weight of the Maine Coon is at least \( 14\frac{3}{4} \) pounds