Question

the distribution of the tuitions, fees, and room and board charges of a random sample. make a frequency distribution for the data. then use the table to estimate the midpoint for \$25,000 or more.\ complete the frequency distribution for the data. (type integers or decimals. do not round.) class x f $15,000 - $17,499 16249.5 7 $17,500 - $19,999 18749.5 11 $20,000 - $22,499 21249.5 13 $22,500 - $24,999 23749.5 9 $25,000 or more 26249.5 6 the sample mean is x = $193495.4 (round to the nearest cent.)

Explanation:

Step1: Recall mid - point formula

For a class interval, the mid - point $x$ is calculated as $\frac{\text{lower limit}+\text{upper limit}}{2}$. For the class "$\$25,000$ or more", if we assume the next class would start at some value higher than $\$25,000$, a common approach is to assume a class width similar to the previous intervals. The previous intervals have a width of $\$2,500$. Let's assume the lower limit of this open - ended class is $\$25,000$ and we can assume an upper limit of $\$27,499$ (to keep the same width as before). Then the mid - point $x=\frac{25000 + 27499}{2}$.

Step2: Calculate the mid - point

$x=\frac{25000+27499}{2}=\frac{52499}{2}=26249.5$

Answer:

$26249.5$