Question

drag and drop the allele combinations into the punnett square using the given genotypes for both parents.
fathers genotype
b
b
mothers genotype
b
b
bb

bb

bb
bb
bb
bbbb

Explanation:

Step1: Analyze top-right cell

Father's allele: \( b \), Mother's allele: \( B \). Genotype: \( Bb \)? Wait, no—wait, Father's genotype alleles are both \( b \) (since the two arrows from father are \( b \) and \( b \)), Mother's are \( B \) and \( b \) (arrows from mother: \( B \) and \( b \)). Wait, top - right cell: father gives \( b \), mother gives \( B \)? Wait no, the father's genotype is such that he can only give \( b \) (both alleles \( b \)? Wait no, the first cell (top - left) is \( Bb \), which is father's \( b \) and mother's \( B \). Wait, let's re - examine.

Father's alleles: the two columns from father are \( b \) and \( b \) (since the blue arrows are \( b \) and \( b \)). Mother's alleles: the two rows from mother are \( B \) and \( b \) (pink arrows \( B \) and \( b \)).

Top - right cell: father's allele \( b \), mother's allele \( B \)? Wait no, the top - right cell is in the column of father's second \( b \) and row of mother's \( B \). So the genotype should be \( Bb \)? Wait no, the first cell (top - left) is \( Bb \) (father's \( b \), mother's \( B \)). Wait, maybe I made a mistake. Wait, the top - right cell: father's allele (column) is \( b \), mother's allele (row) is \( B \), so the genotype is \( Bb \)? No, wait the options on the left have \( Bb \), \( bb \), \( BB \), \( bbBb \) (which is invalid). Wait, no—wait, the father's genotype: both his alleles are \( b \) (since the two arrows from him are \( b \)), mother's alleles are \( B \) and \( b \) (arrows \( B \) and \( b \)).

So for the top - right cell: father gives \( b \), mother gives \( B \)? No, wait the mother's first row is \( B \), second row is \( b \). Father's first column is \( b \), second column is \( b \).

Top - right cell: column (father) \( b \), row (mother) \( B \): genotype \( Bb \)? But the first cell (top - left) is \( Bb \) (father \( b \), mother \( B \)). Wait, no—maybe the father's genotype is \( Bb \)? Wait, the first cell is \( Bb \), which would be father's \( B \) and mother's \( B \)? No, the blue arrow is \( b \). Wait, I think I messed up. Let's start over.

Father's genotype: the two alleles he can pass are \( b \) and \( b \) (since the two blue arrows are \( b \)). Mother's genotype: the two alleles she can pass are \( B \) and \( b \) (pink arrows \( B \) and \( b \)).

Top - right cell: father's allele \( b \), mother's allele \( B \): genotype \( Bb \)? But the left - hand options have \( Bb \), \( bb \), \( BB \), \( bbBb \). Wait, no—wait the bottom - left cell: father's \( b \), mother's \( B \)? No, bottom - left cell is father's \( b \) (second column? No, father's columns are two \( b \)s, mother's rows are \( B \) and \( b \)).

Wait, bottom - left cell: father's \( b \) (second column), mother's \( B \) (first row)? No, bottom - left cell is in father's second \( b \) column and mother's \( B \) row? No, the Punnett square is 2x2. Rows: mother's alleles ( \( B \) and \( b \) ), columns: father's alleles ( \( b \) and \( b \) ).

So cell (1,1) (top - left): mother \( B \), father \( b \) → \( Bb \)

Cell (1,2) (top - right): mother \( B \), father \( b \) → \( Bb \)

Cell (2,1) (bottom - left): mother \( b \), father \( b \) → \( bb \)? No, wait mother's second row is \( b \), father's first column is \( b \): \( bb \)? Wait, the bottom - right cell is \( bb \) (mother \( b \), father \( b \)).

Wait, the bottom - left cell: mother \( b \), father \( b \)? No, mother's second row is \( b \), father's first column is \( b \): \( bb \)? But the left - hand options have \( bb \). Wait, the top - right cell: mother \( B \), father \( b \) → \( Bb \), bottom - left cell: mother \( b \), father \( b \) → \( bb \)? No, wait the bottom - left cell is in father's second \( b \) column and mother's \( B \) row? No, I'm confused. Let's use the Punnett square rules.

Father's genotype: let's assume father is \( bb \) (homozygous recessive), mother is \( Bb \) (heterozygous).

Punnett square:

| | \( b \) | \( b \) |
|---|---|---|
| \( B \) | \( Bb \) | \( Bb \) |
| \( b \) | \( bb \) | \( bb \) |

Ah! So the top - right cell (where father is \( b \), mother is \( B \)) is \( Bb \), the bottom - left cell (father \( b \), mother \( b \)) is \( bb \)? Wait no, in the table above, the bottom - left cell is \( bb \) (mother \( b \), father \( b \)), bottom - right is \( bb \) (mother \( b \), father \( b \)). Wait, the given bottom - right cell is \( bb \), which matches. So the top - right cell should be \( Bb \), and the bottom - left cell should be \( bb \)? Wait no, in the given diagram, the bottom - right cell is \( bb \) (mother \( b \), father \( b \)), so the bottom - left cell (mother \( b \), father \( b \))? No, mother's first row is \( B \), second row is \( b \). Father's first column is \( b \), second column is \( b \).

So:

Top - left: mother \( B \), father \( b \) → \( Bb \) (given)

Top - right: mother \( B \), father \( b \) → \( Bb \)

Bottom - left: mother \( b \), father \( b \) → \( bb \)

Bottom - right: mother \( b \), father \( b \) → \( bb \) (given)

So the top - right cell should be \( Bb \), and the bottom - left cell should be \( bb \).

Step2: Match with options

The left - hand options are \( Bb \), \( bb \), \( BB \), \( bbBb \) (invalid). So for the top - right cell, we need to drag \( Bb \), and for the bottom - left cell, we need to drag \( bb \).

Answer:

Top - right cell: \( Bb \)

Bottom - left cell: \( bb \)