Question

each of two parents has the genotype green/blue, which consists of the pair of alleles that determine eye color. each parent contributes one of those alleles to a child. assume that if the child has at least one green allele, that allele will dominate and the childs eye color will be green. a. list the different possible outcomes. assume that these outcomes are equally likely. b. what is the probability that a child of these parents will have the blue/blue genotype? c. what is the probability that the child will have green eye color? a. list the possible outcomes. a. green/green and blue/blue b. green/green, green/blue, and blue/blue c. green/green, green/blue, blue/green, and blue/blue d. green/blue and blue/green

Explanation:

Step1: Analyze allele - contribution

Each parent has alleles green and blue. When they contribute alleles to a child, we consider all possible combinations.
The first parent can contribute either green or blue, and for each contribution of the first parent, the second parent can also contribute either green or blue.
If the first parent contributes green and the second parent contributes green, the child has green/green genotype.
If the first parent contributes green and the second parent contributes blue, the child has green/blue genotype.
If the first parent contributes blue and the second parent contributes green, the child has blue/green genotype.
If the first parent contributes blue and the second parent contributes blue, the child has blue/blue genotype.

Step2: Calculate total number of outcomes

There are 4 possible outcomes: green/green, green/blue, blue/green, blue/blue.

Step3: Calculate probability of blue/blue genotype

Since there are 4 equally - likely outcomes and only 1 is blue/blue, the probability of blue/blue genotype is $\frac{1}{4}$.

Step4: Calculate probability of green eye - color

A child has green eye - color if it has at least one green allele. The non - green - eye - color outcome is blue/blue. So the number of green - eye - color outcomes is 3 (green/green, green/blue, blue/green). The probability of green eye - color is $\frac{3}{4}$.

Answer:

a. C. green/green, green/blue, blue/green, and blue/blue
b. $\frac{1}{4}$
c. $\frac{3}{4}$