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at the end of each month, tamera records the height of her plant on the…

Question

at the end of each month, tamera records the height of her plant on the line graph. during which month was her plants growth rate greatest? month 1 month 2 month 4 month 6

Explanation:

Step1: Recall growth - rate concept

Growth rate is change in height per unit time. On a line - graph of height vs time, it is the slope of the line segment between two points.

Step2: Calculate slopes for each month

For month 1: Let $(x_1,y_1)=(0,0)$ and $(x_2,y_2)=(1,3)$. Slope $m_1=\frac{y_2 - y_1}{x_2 - x_1}=\frac{3 - 0}{1 - 0}=3$.
For month 2: Let $(x_1,y_1)=(1,3)$ and $(x_2,y_2)=(2,5)$. Slope $m_2=\frac{y_2 - y_1}{x_2 - x_1}=\frac{5 - 3}{2 - 1}=2$.
For month 4: Let $(x_1,y_1)=(3,6)$ and $(x_2,y_2)=(4,7)$. Slope $m_4=\frac{y_2 - y_1}{x_2 - x_1}=\frac{7 - 6}{4 - 3}=1$.
For month 6: Let $(x_1,y_1)=(5,8)$ and $(x_2,y_2)=(6,9)$. Slope $m_6=\frac{y_2 - y_1}{x_2 - x_1}=\frac{9 - 8}{6 - 5}=1$.

Step3: Compare slopes

Since $m_1 = 3$, $m_2=2$, $m_4 = 1$, $m_6 = 1$, the largest slope is $m_1$.

Answer:

month 1