QUESTION IMAGE
Question
equivalent ratios
write two equivalent ratios.
1)
2)
4)
5)
determine whether the ratios are equivalent.
- (\frac{7}{9}) and (\frac{49}{63})
- (\frac{3}{7}) and (\frac{5}{2})
- (\frac{9}{2}) and (\frac{45}{10})
- (\frac{2}{9}) and (\frac{9}{5})
Problem 1: Write two equivalent ratios for \( \frac{5}{9} \)
Step 1: Multiply numerator and denominator by 2
To find an equivalent ratio, we can multiply both the numerator and the denominator of the ratio \( \frac{5}{9} \) by the same non - zero number. Let's multiply by 2.
\( \frac{5\times2}{9\times2}=\frac{10}{18} \)
Step 2: Multiply numerator and denominator by 3
Now, multiply the numerator and denominator of \( \frac{5}{9} \) by 3.
\( \frac{5\times3}{9\times3}=\frac{15}{27} \)
Step 1: Multiply numerator and denominator by 2
Multiply both the numerator and denominator of \( \frac{4}{9} \) by 2.
\( \frac{4\times2}{9\times2}=\frac{8}{18} \)
Step 2: Multiply numerator and denominator by 3
Multiply the numerator and denominator of \( \frac{4}{9} \) by 3.
\( \frac{4\times3}{9\times3}=\frac{12}{27} \)
Step 1: Multiply numerator and denominator by 2
Multiply both the numerator and denominator of \( \frac{9}{11} \) by 2.
\( \frac{9\times2}{11\times2}=\frac{18}{22} \)
Step 2: Multiply numerator and denominator by 3
Multiply the numerator and denominator of \( \frac{9}{11} \) by 3.
\( \frac{9\times3}{11\times3}=\frac{27}{33} \)
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Two equivalent ratios for \( \frac{5}{9} \) are \( \frac{10}{18} \) and \( \frac{15}{27} \)