Question

erick has a collection of 8 brown fingerboards, 4 green fingerboards, and 4 silver fingerboards. he chooses one at random. locate the probability of the following events on the number line: a green fingerboard is chosen. a blue fingerboard is chosen.

Explanation:

Step1: Calculate total fingerboards

$8 + 4 + 4 = 16$

Step2: Find probability of green fingerboard

$\text{Probability} = \frac{\text{Number of green fingerboards}}{\text{Total fingerboards}} = \frac{4}{16} = \frac{1}{4}$

Step3: Locate $\frac{1}{4}$ on number line

The number line from 0 to 1 is split into 4 equal segments: $0$ (A), $\frac{1}{4}$ (B), $\frac{1}{2}$ (C), $\frac{3}{4}$ (D), $1$ (E). So $\frac{1}{4}$ corresponds to point B.

Step4: Find probability of blue fingerboard

There are 0 blue fingerboards, so $\text{Probability} = \frac{0}{16} = 0$, which corresponds to point A.

Answer:

1. A green fingerboard is chosen: Point B
2. A blue fingerboard is chosen: Point A