Question

fernandos class sold chocolate bars as a fundraiser for a field trip. the 6 students sold: 57 chocolate bars 51 chocolate bars 19 chocolate bars 99 chocolate bars 33 chocolate bars 80 chocolate bars. what was the mean absolute deviation of the numbers of chocolate bars sold? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): chocolate bars

Explanation:

Step1: Calculate the mean

The data set is \(57,51,19,99,33,80\). The mean \(\bar{x}=\frac{57 + 51+19+99+33+80}{6}=\frac{339}{6}=56.5\).

Step2: Calculate the absolute - deviations

\(\vert57 - 56.5\vert=0.5\), \(\vert51 - 56.5\vert = 5.5\), \(\vert19 - 56.5\vert=37.5\), \(\vert99 - 56.5\vert = 42.5\), \(\vert33 - 56.5\vert=23.5\), \(\vert80 - 56.5\vert = 23.5\).

Step3: Calculate the mean of the absolute - deviations

\(MAD=\frac{0.5 + 5.5+37.5+42.5+23.5+23.5}{6}=\frac{132}{6}=22\).

Answer:

22