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find the indicated complement. a certain group of women has a 0.99% rat…

Question

find the indicated complement.
a certain group of women has a 0.99% rate of red/green color blindness. if a woman is randomly selected, what is the probability that she does not have red/green color blindness?

the probability that the woman selected does not have red/green color blindness is
(type an integer or a decimal. do not round )

Explanation:

Step1: Convert percentage to decimal

The rate of red/green color blindness is 0.99%, which is $0.99\%=\frac{0.99}{100} = 0.0099$.

Step2: Use complement rule

The complement rule states that $P(\text{not } A)=1 - P(A)$. Let $A$ be the event that a woman has red/green color blindness. Then the probability that a woman does not have red/green color blindness is $1 - 0.0099$.
Calculating $1 - 0.0099 = 0.9901$.

Answer:

0.9901