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and find the missing values. 1) | x | 9 | | 5 | | | y | 36 | 16 | | 8 |…

Question

and find the missing values.
1)

x95
y36168

2)

x6159
y42

3)

x123048
y38

4)

x4
y25402060

5)

x7114
y3224

6)

x14
y216153

7)

x530
y14612

8)

x347
y1854

Explanation:

1)

Step1: Find x-y relationship

From $x=9, y=36$: $y=4x$ or $x=\frac{y}{4}$

Step2: Find missing x (y=16)

$x=\frac{16}{4}=4$

Step3: Find missing y (x=5)

$y=4\times5=20$

Step4: Find missing x (y=8)

$x=\frac{8}{4}=2$

2)

Step1: Find x-y relationship

From $x=6, y=2$: $y=\frac{x}{3}$ or $x=3y$

Step2: Find missing x (y=4)

$x=3\times4=12$

Step3: Find missing y (x=15)

$y=\frac{15}{3}=5$

Step4: Find missing y (x=9)

$y=\frac{9}{3}=3$

3)

Step1: Find x-y relationship

From $x=48, y=8$: $\frac{x}{y}=6$ → $x=6y$ or $y=\frac{x}{6}$

Step2: Find missing y (x=12)

$y=\frac{12}{6}=2$

Step3: Find missing x (y=3)

$x=6\times3=18$

Step4: Find missing y (x=30)

$y=\frac{30}{6}=5$

4)

Step1: Find x-y relationship

From $x=4, y=20$: $x\times y=80$ (inverse variation)

Step2: Find missing x (y=25)

$x=\frac{80}{25}=3.2$

Step3: Find missing x (y=40)

$x=\frac{80}{40}=2$

Step4: Find missing x (y=60)

$x=\frac{80}{60}=\frac{4}{3}\approx1.33$

5)

Step1: Find x-y relationship

From $x=4, y=32$: $x\times y=128$ (inverse variation)

Step2: Find missing y (x=7)

$y=\frac{128}{7}\approx18.29$

Step3: Find missing y (x=11)

$y=\frac{128}{11}\approx11.64$

Step4: Find missing x (y=24)

$x=\frac{128}{24}=\frac{16}{3}\approx5.33$

6)

Step1: Find x-y relationship

From $x=14, y=6$: $x\times y=84$ (inverse variation)

Step2: Find missing x (y=21)

$x=\frac{84}{21}=4$

Step3: Find missing x (y=15)

$x=\frac{84}{15}=5.6$

Step4: Find missing x (y=3)

$x=\frac{84}{3}=28$

7)

Step1: Find x-y relationship

From $x=30, y=12$: $x\times y=360$ (inverse variation)

Step2: Find missing x (y=14)

$x=\frac{360}{14}=\frac{180}{7}\approx25.71$

Step3: Find missing y (x=5)

$y=\frac{360}{5}=72$

Step4: Find missing x (y=6)

$x=\frac{360}{6}=60$

8)

Step1: Find x-y relationship

From $x=3, y=18$: $y=6x$

Step2: Find missing y (x=4)

$y=6\times4=24$

Step3: Find missing x (y=54)

$x=\frac{54}{6}=9$

Step4: Find missing y (x=7)

$y=6\times7=42$

Answer:

  1. Missing values: $x=4$, $y=20$, $x=2$
  2. Missing values: $x=12$, $y=5$, $y=3$
  3. Missing values: $y=2$, $x=18$, $y=5$
  4. Missing values: $x=3.2$, $x=2$, $x=\frac{4}{3}$
  5. Missing values: $y=\frac{128}{7}$, $y=\frac{128}{11}$, $x=\frac{16}{3}$
  6. Missing values: $x=4$, $x=5.6$, $x=28$
  7. Missing values: $x=\frac{180}{7}$, $y=72$, $x=60$
  8. Missing values: $y=24$, $x=9$, $y=42$