Question

find the probability of z occurring in the indicated region of the standard normal distribution. click here to view page 1 of the standard normal table. click here to view page 2 of the standard normal table. p(0 < z < 1.78)= (round to four decimal places as needed.)

Explanation:

Step1: Recall standard - normal table use

The standard - normal table gives $P(Z < z)$.

Step2: Use the property of normal distribution

We know that $P(0 < Z < 1.78)=P(Z < 1.78)-P(Z < 0)$.
From the standard - normal table, $P(Z < 1.78) = 0.9625$ and $P(Z < 0)=0.5$.

Step3: Calculate the probability

$P(0 < Z < 1.78)=0.9625 - 0.5=0.4625$.

Answer:

$0.4625$