QUESTION IMAGE
Question
five hundred consumers were surveyed about a new brand of snack food, crunchicles. their age groups and preferences are given in the table.
| 18 - 24 | 25 - 34 | 35 - 55 | 55 and over | total | |
|---|---|---|---|---|---|
| disliked crunchicles | 22 | 63 | 25 | 122 | 232 |
| no preference | 23 | 28 | 19 | 28 | 98 |
| total | 91 | 98 | 71 | 240 | 500 |
one consumer from the survey is selected at random. use reduced fractions for your responses to each of the following questions.
what is the probability that the consumer is 18 - 24 years of age, given that he/she dislikes crunchicles?
what is the probability that the selected consumer dislikes crunchicles?
what is the probability that the selected consumer is 35 - 55 years old or likes crunchicles?
if the selected consumer is 70 years old, what is the probability that he/she likes crunchicles?
Step1: Recall conditional - probability formula
The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}$. For the first question, let $A$ be the event that the consumer is 18 - 24 years old and $B$ be the event that the consumer dislikes Crunchicles.
$P(A\cap B)=\frac{22}{500}$ and $P(B)=\frac{232}{500}$, so $P(A|B)=\frac{22/500}{232/500}=\frac{22}{232}=\frac{11}{116}$.
Step2: Find probability of disliking Crunchicles
The number of consumers who dislike Crunchicles is 232 out of 500. So the probability $P(\text{dislike})=\frac{232}{500}=\frac{58}{125}$.
Step3: Use the addition - rule for probability
The addition - rule for probability is $P(A\cup B)=P(A)+P(B)-P(A\cap B)$. Let $A$ be the event that the consumer is 35 - 55 years old and $B$ be the event that the consumer likes Crunchicles. $P(A)=\frac{71}{500}$, $P(B)=\frac{170}{500}$, and $P(A\cap B)=\frac{27}{500}$. Then $P(A\cup B)=\frac{71 + 170-27}{500}=\frac{214}{500}=\frac{107}{250}$.
Step4: Since 70 years old is in the 55 and over age group
Let $A$ be the event that the consumer likes Crunchicles and $B$ be the event that the consumer is 55 and over. $P(A\cap B)=\frac{90}{500}$ and $P(B)=\frac{240}{500}$, so $P(A|B)=\frac{90/500}{240/500}=\frac{90}{240}=\frac{3}{8}$.
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$\frac{11}{116}$
$\frac{58}{125}$
$\frac{107}{250}$
$\frac{3}{8}$