Question

forty people were randomly sampled and surveyed as to the number of pets in their household. the results are listed below: 1 1 0 4 1 0 1 2 3 5 2 0 2 0 3 1 2 0 0 1 0 4 0 0 3 1 0 0 2 1 0 0 4 0 1 3 5 0 2 1 what is the best frequency table for these data? a. pet survey number of pets tally frequency 0 15 1 10 2 6 3 4 4 3 5 2 c. pet survey number of pets tally frequency 0 10 1 15 2 4 3 6 4 2 5 3 mark this and return

Explanation:

Step1: Count number of 0s

Go through the data and count how many times 0 appears. The data points with 0: 0 (from first row), 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0? Wait, let's list all:

First row: 0 (3rd), 0 (6th)
Second row: 0 (4th), 0 (6th)
Third row: 0 (2nd), 0 (3rd), 0 (5th), 0 (7th), 0 (8th)
Fourth row: 0 (3rd), 0 (4th), 0 (7th), 0 (8th)
Fifth row: 0 (2nd), 0 (6th)

Wait, better way: let's count each number:

Number of 0s: Let's count each 0 in the data:

First row: 0 (index 3), 0 (index 6) → 2
Second row: 0 (index 4), 0 (index 6) → 2 (total 4)
Third row: 0 (index 2), 0 (index 3), 0 (index 5), 0 (index 7), 0 (index 8) → 5 (total 9)
Fourth row: 0 (index 3), 0 (index 4), 0 (index 7), 0 (index 8) → 4 (total 13)
Fifth row: 0 (index 2), 0 (index 6) → 2 (total 15). So 0 appears 15 times.

Number of 1s: Let's count:

First row: 1 (1st), 1 (2nd), 1 (5th), 1 (7th) → 4
Second row: 1 (8th) → 1 (total 5)
Third row: 1 (4th) → 1 (total 6)
Fourth row: 1 (2nd), 1 (6th) → 2 (total 8)
Fifth row: 1 (3rd), 1 (8th) → 2 (total 10). So 1 appears 10 times.

Number of 2s:

First row: 2 (8th) → 1
Second row: 2 (3rd), 2 (5th) → 2 (total 3)
Third row: 2 (1st) → 1 (total 4)
Fourth row: 2 (5th) → 1 (total 5)
Fifth row: 2 (7th) → 1 (total 6). So 2 appears 6 times? Wait no, wait:

Wait first row: 2 (8th) → 1

Second row: 2 (3rd), 2 (5th) → 2 (total 3)

Third row: 2 (1st) → 1 (total 4)

Fourth row: 2 (5th) → 1 (total 5)

Fifth row: 2 (7th) → 1 (total 6). Wait but let's recount:

Data points with 2:

Row 1: 2 (position 8) → 1

Row 2: 2 (position 3), 2 (position 5) → 2 (total 3)

Row 3: 2 (position 1) → 1 (total 4)

Row 4: 2 (position 5) → 1 (total 5)

Row 5: 2 (position 7) → 1 (total 6). So 2 appears 6 times? Wait no, maybe I made a mistake. Wait the options:

Option a: 0:15, 1:10, 2:6, 3:4, 4:3, 5:2

Option c: 0:10, 1:15, 2:4, 3:6, 4:2, 5:3

Wait let's check 3s:

Number of 3s:

Row 2: 3 (1st), 3 (7th) → 2

Row 3: 3 (6th) → 1 (total 3)

Row 4: 3 (1st) → 1 (total 4)

Row 5: 3 (4th) → 1 (total 5). Wait no, let's list all 3s:

Row 2: 3 (1st), 3 (7th) → 2

Row 3: 3 (6th) → 1 (total 3)

Row 4: 3 (1st) → 1 (total 4)

Row 5: 3 (4th) → 1 (total 5). Wait but option a has 3:4, option c has 3:6. Wait maybe my counting is wrong. Let's use a better approach:

Let's list all data points:

Row 1: 1,1,0,4,1,0,1,2 → 8 numbers

Row 2: 3,5,2,0,2,0,3,1 → 8

Row 3: 2,0,0,1,0,4,0,0 → 8

Row 4: 3,1,0,0,2,1,0,0 → 8

Row 5: 4,0,1,3,5,0,2,1 → 8

Total 5 rows ×8=40 numbers.

Now count each number:

0:

Row1: positions 3,6 → 2

Row2: positions 4,6 → 2 (total 4)

Row3: positions 2,3,5,7,8 → 5 (total 9)

Row4: positions 3,4,7,8 → 4 (total 13)

Row5: positions 2,6 → 2 (total 15). So 0:15.

1:

Row1: positions 1,2,5,7 → 4

Row2: position 8 → 1 (total 5)

Row3: position 4 → 1 (total 6)

Row4: positions 2,6 → 2 (total 8)

Row5: positions 3,8 → 2 (total 10). So 1:10.

2:

Row1: position 8 → 1

Row2: positions 3,5 → 2 (total 3)

Row3: position 1 → 1 (total 4)

Row4: position 5 → 1 (total 5)

Row5: position 7 → 1 (total 6). So 2:6.

3:

Row2: positions 1,7 → 2

Row4: position 1 → 1 (total 3)

Row5: position 4 → 1 (total 4). So 3:4.

4:

Row1: position 4 → 1

Row3: position 6 → 1 (total 2)

Row5: position 1 → 1 (total 3). So 4:3.

5:

Row2: position 2 → 1

Row5: position 5 → 1 (total 2). So 5:2.

Now check the options:

Option a:

0:15, 1:10, 2:6, 3:4, 4:3, 5:2 → matches our counts.

Option c:

0:10, 1:15, 2:4, 3:6, 4:2, 5:3 → does not match.

So the correct frequency table is option a.

Answer:

a. Pet Survey

Number of Pets	Tally	Frequency
1									(10)	10
2						(6)	6
3					(4)	4
4				(3)	3
5			(2)	2