Question

a grain of sand has a diameter that is 60 μm long. under a microscope, it looks 48,000 μm long. what magnification scale was used? hint: scale factor = \frac{scaled image dimension}{original dimension}

Explanation:

Step1: Identify values

Scaled image dimension = 48000 $\mu$m, original dimension = 60 $\mu$m.

Step2: Apply scale - factor formula

Scale Factor=$\frac{\text{Scaled Image Dimension}}{\text{Original Dimension}}=\frac{48000}{60}$

Step3: Calculate result

$\frac{48000}{60}=800$

Answer:

800