Question

in a group of budgerigar parakeets, some individuals have green body feathers and others have blue body feathers. in this group, the gene for the body feather color trait has two alleles. the allele for green body feathers (b) is dominant over the allele for blue body feathers (b). this punnett square shows a cross between two budgerigar parakeets. what is the probability that a budgerigar parakeet produced by this cross will be heterozygous for the body feather color gene? %

Explanation:

Step1: Count total Punnett square outcomes

Total genotypes = 4 (Bb, Bb, bb, bb)

Step2: Count heterozygous (Bb) outcomes

Heterozygous genotypes = 2

Step3: Calculate probability percentage

$\text{Probability (\%)} = \frac{\text{Number of Bb genotypes}}{\text{Total genotypes}} \times 100 = \frac{2}{4} \times 100$

Answer:

50%