Question

in a group of chickens, some individuals have white legs and others have yellow legs. in this group, the gene for the leg color trait has two alleles. the allele for white legs (l) is dominant over the allele for yellow legs (l). this punnett square shows a cross between two chickens. what is the probability that a chicken produced by this cross will have white legs? \\(\frac{0}{4}\\) \\(\frac{1}{4}\\) \\(\frac{2}{4}\\) \\(\frac{3}{4}\\) \\(\frac{4}{4}\\)

Explanation:

Step1: Determine Genotypes with White Legs

White legs are dominant (L), so genotypes LL, Ll, Ll will show white legs. From the Punnett square, the genotypes are LL, Ll, Ll, ll. So white - leg genotypes are LL, Ll, Ll (3 out of 4).

Step2: Calculate Probability

Probability is the number of favorable outcomes (white - leg genotypes) over total outcomes. Total squares in Punnett square are 4. Favorable (white legs) are 3. So probability is $\frac{3}{4}$.

Answer:

$\frac{3}{4}$ (or the option corresponding to $\frac{3}{4}$ in the given choices)