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hardy - weinberg equations equation 1: p + q = 1 p = frequency of domin…

Question

hardy - weinberg equations
equation 1: p + q = 1
p = frequency of dominant allele
q = frequency of recessive allele

equation 2: p²+2pq + q² = 1
p² = frequency of homozygous dominant individuals
2pq = frequency of heterozygous individuals
q² = frequency of homozygous recessive individuals

what is represented by p - squared in the second equation?
percentage of heterozygous individuals
percentage of homozygous recessive individuals
percentage of individuals that express the dominant allele
percentage of homozygous dominant individuals

Explanation:

Brief Explanations

In the Hardy - Weinberg equation $p^{2}+2pq + q^{2}=1$, $p^{2}$ represents the frequency (or percentage) of homozygous dominant individuals where $p$ is the frequency of the dominant allele.

Answer:

D. percentage of homozygous dominant individuals