Question

in humans, the trait for eye color has multiple alleles; however, the brown - eye allele is dominant to the blue - eye allele. if two people who are heterozygous for the trait of brown eyes mate, what is the likely genotypic and phenotypic ratios of the offspring? the offspring has the possibility of having, 25% chance of their genotype being, chance of their genotype being and chance of their genotype being bb.

Explanation:

Step1: Define alleles

Let B represent the brown - eye allele and b represent the blue - eye allele. Heterozygous parents have genotype Bb.

Step2: Set up Punnett - square

	B	b
b	Bb	bb

Step3: Calculate genotypes

From the Punnett - square, there is 1 BB out of 4 (25% chance), 2 Bb out of 4 (50% chance), and 1 bb out of 4 (25% chance).

Step4: Determine phenotypes

Since B is dominant over b, BB and Bb result in brown eyes, and bb results in blue eyes. So, the phenotypic ratio is 3 brown - eyed : 1 blue - eyed.

Answer:

The offspring has the possibility of having brown eyes or blue eyes, 25% chance of their genotype being BB, 50% chance of their genotype being Bb and 25% chance of their genotype being bb.