Question

identify the lower class limits, upper class limits, class width, class mid - points, and class boundaries for the given frequency distribution. also identify the number of individuals included in the summary.
age (yr) when award was won frequency
25 - 29 28
30 - 34 36
35 - 39 12
40 - 44 2
45 - 49 5
50 - 54 2
55 - 59 1
identify the lower class limits.
25, 30, 35, 40, 45, 50, 55
(type integers or decimals. do not round. use ascending order.)
identify the upper class limits.
29, 34, 39, 44, 49, 54, 59
(type integers or decimals. do not round. use ascending order.)
identify the class width.
5
(type an integer or a decimal. do not round.)
identify the class mid - points.
27, 32, 37, 42, 47, 52, 57
(type integers or decimals. do not round. use ascending order.)
identify the class boundaries.
(type integers or decimals. do not round. use ascending order.)

Explanation:

Step1: Find lower class boundaries

Subtract 0.5 from the lower class limits. For the first class with lower - class limit 25, the lower - class boundary is $25 - 0.5=24.5$.

Step2: Find upper class boundaries

Add 0.5 to the upper class limits. For the first class with upper - class limit 29, the upper - class boundary is $29 + 0.5 = 29.5$.

Step3: Calculate all class boundaries

For the class limits 25 - 29: lower boundary is 24.5 and upper boundary is 29.5; for 30 - 34: lower boundary is $30 - 0.5=29.5$ and upper boundary is $34 + 0.5 = 34.5$; for 35 - 39: lower boundary is $35 - 0.5 = 34.5$ and upper boundary is $39+0.5 = 39.5$; for 40 - 44: lower boundary is $40 - 0.5 = 39.5$ and upper boundary is $44 + 0.5 = 44.5$; for 45 - 49: lower boundary is $45 - 0.5 = 44.5$ and upper boundary is $49 + 0.5 = 49.5$; for 50 - 54: lower boundary is $50 - 0.5 = 49.5$ and upper boundary is $54 + 0.5 = 54.5$; for 55 - 59: lower boundary is $55 - 0.5 = 54.5$ and upper boundary is $59 + 0.5 = 59.5$.

Answer:

24.5, 29.5, 34.5, 39.5, 44.5, 49.5, 54.5, 59.5