Question

jeanette took two tests. find her z - score for each test. (remember: the number of standard deviations betv and the mean score is indicated by a z - score.) on which did she score better compared with others in her cl
test a test b
jeanettes score 90 95
mean score 64 60
standard deviation 8 10
a. test a: 3.25; test b: 3.5; test b
c. test a: 26; test b: 35; test b
b. test a: 3.5; test b: 3.25; test a
d. test a: 3.25; test b: 3.5; test a
please select the best answer from the choices provided
a
b
c
d

Explanation:

Step1: Recall z - score formula

The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $x$ is the individual score, $\mu$ is the mean, and $\sigma$ is the standard deviation.

Step2: Calculate z - score for Test A

For Test A, $x = 90$, $\mu=64$, $\sigma = 8$. Then $z_A=\frac{90 - 64}{8}=\frac{26}{8}=3.25$.

Step3: Calculate z - score for Test B

For Test B, $x = 95$, $\mu = 60$, $\sigma=10$. Then $z_B=\frac{95 - 60}{10}=\frac{35}{10}=3.5$.

Step4: Compare z - scores

Since $3.5>3.25$, Jeanette scored better on Test B compared to others in her class.

Answer:

A. Test A: 3.25; Test B: 3.5; Test B