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Question
2 la largeur, en mètres, d’un rectangle est égale à s. écris une expression pour la longueur sachant que celle-ci a: (a) 2 m de plus que la largeur; (b) 1 m de moins que le double de la largeur.
Part (a)
Step 1: Understand the relationship
The length is 2 meters more than the width. The width is \( s \) meters.
Step 2: Form the expression
To find the length, we add 2 to the width \( s \). So the expression for the length is \( s + 2 \).
Part (b)
Step 1: Understand the relationship
The length is 1 meter less than double the width. Double the width is \( 2\times s=2s \).
Step 2: Form the expression
To find the length, we subtract 1 from \( 2s \). So the expression for the length is \( 2s - 1 \).
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s:
(a) The length is \( \boldsymbol{s + 2} \) meters.
(b) The length is \( \boldsymbol{2s - 1} \) meters.