Question

and leave the labrador with a yellow coat.
complete the following dihybrid punnett square.
bbee × bbee
f = be
o = be
i = be
l = be
genotype:
phenotype:

Explanation:

Step1: List all genotypes from Punnett square

Identify each unique genotype and count occurrences:

• BBEE: 1
• BBEe: 2
• BBee: 1
• BbEE: 2
• BbEe: 4
• Bbee: 2
• bbEE: 1
• bbEe: 2
• bbee: 1

Step2: Calculate genotype ratio

Sum all counts: $1+2+1+2+4+2+1+2+1=16$
Ratio: $BBEE:BBEe:BBee:BbEE:BbEe:Bbee:bbEE:bbEe:bbee = 1:2:1:2:4:2:1:2:1$

Step3: Map genotypes to phenotypes

Use the given phenotype rules:

• Black: BBEE, BBEe, BbEE, BbEe (count: $1+2+2+4=9$)
• Brown: bbEE, bbEe (count: $1+2=3$)
• Yellow: BBee, Bbee, bbee (count: $1+2+1=4$)

Step4: Calculate phenotype ratio

Ratio: $Black:Brown:Yellow = 9:3:4$

Answer:

Genotype Ratio:

$BBEE:BBEe:BBee:BbEE:BbEe:Bbee:bbEE:bbEe:bbee = 1:2:1:2:4:2:1:2:1$

Phenotype Ratio:

$Black:Brown:Yellow = 9:3:4$