Question

maria checked the hit counters of 6 websites to track how many people visited them yesterday. she noted: 3 visitors, 6 visitors, 6 visitors, 6 visitors, 9 visitors, 3 visitors. what was the mean absolute deviation of the numbers of visitors? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): visitors

Explanation:

Step1: Calculate the mean

First, find the sum of the data values: \(3 + 6 + 6 + 6 + 9 + 3 = 33\).
There are 6 data points, so the mean \(\bar{x}=\frac{33}{6}=5.5\).

Step2: Find absolute deviations

Calculate the absolute deviation of each data point from the mean:

• For \(3\): \(|3 - 5.5| = 2.5\) (there are two \(3\)s, so two \(2.5\)s)
• For \(6\): \(|6 - 5.5| = 0.5\) (there are three \(6\)s, so three \(0.5\)s)
• For \(9\): \(|9 - 5.5| = 3.5\) (one \(9\))

Step3: Calculate the mean of absolute deviations

Sum the absolute deviations: \((2.5\times2)+(0.5\times3)+3.5 = 5 + 1.5 + 3.5 = 10\).
Divide by the number of data points (\(6\)): \(\text{MAD}=\frac{10}{6}\approx1.7\) (rounded to the nearest tenth).

Answer:

\(1.7\)