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5. the mass of the celery at 0 hours was 7.21 g. the mass of the celery…

Question

  1. the mass of the celery at 0 hours was 7.21 g. the mass of the celery at 6 hours was 7.17 g. in this activity we will calculate the % change in mass to account for different starting masses in all of the samples. calculate the % change in mass of the celery. hint: make sure that you include a negative sign if the celery lost mass. percent change = \\(\frac{final - initial}{initial} \times 100\\) % change in mass the answer to this question depends on your answers to previous questions.

Explanation:

Step1: Identify given values

Initial mass $m_i = 7.21$ g, Final mass $m_f = 7.17$ g

Step2: Calculate mass difference

$m_f - m_i = 7.17 - 7.21 = -0.04$ g

Step3: Apply percent change formula

$\text{Percent Change} = \frac{m_f - m_i}{m_i} \times 100 = \frac{-0.04}{7.21} \times 100$

Step4: Compute final value

$\frac{-0.04}{7.21} \times 100 \approx -0.55$

Answer:

-0.55%