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4. \\(\frac{1}{3}x^2 + 14 = 26\\)

Question

  1. \\(\frac{1}{3}x^2 + 14 = 26\\)

Explanation:

Step1: Subtract 14 from both sides

$\frac{1}{3}x^{2}+14 - 14=26 - 14$
$\frac{1}{3}x^{2}=12$

Step2: Multiply both sides by 3

$3\times\frac{1}{3}x^{2}=12\times3$
$x^{2}=36$

Step3: Take square root of both sides

$x = \pm\sqrt{36}$
$x=\pm6$

Answer:

$x = 6$ or $x=- 6$