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Question
- \\(\frac{1}{3}x^2 + 14 = 26\\)
Step1: Subtract 14 from both sides
$\frac{1}{3}x^{2}+14 - 14=26 - 14$
$\frac{1}{3}x^{2}=12$
Step2: Multiply both sides by 3
$3\times\frac{1}{3}x^{2}=12\times3$
$x^{2}=36$
Step3: Take square root of both sides
$x = \pm\sqrt{36}$
$x=\pm6$
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$x = 6$ or $x=- 6$