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b. f(x) = x² + 9

Question

b. f(x) = x² + 9

Explanation:

Response

Assuming the problem is to find the derivative of \( f(x)=x^{2}+9 \) (a common calculus task with such a function):

Step1: Recall power rule for derivatives

The power rule states that if \( y = x^n \), then \( y'=nx^{n - 1} \). Also, the derivative of a constant \( c \) is \( 0 \), i.e., \( \frac{d}{dx}(c)=0 \).

Step2: Differentiate term by term

For the term \( x^{2} \), using the power rule with \( n = 2 \), we get \( \frac{d}{dx}(x^{2})=2x^{2-1}=2x \).
For the term \( 9 \) (a constant), its derivative is \( \frac{d}{dx}(9) = 0 \).

Step3: Combine the derivatives

The derivative of \( f(x)=x^{2}+9 \) is the sum of the derivatives of its terms: \( f'(x)=2x + 0=2x \).

Answer:

If finding the derivative, the derivative \( f'(x)=2x \); if other operations (like finding roots, domain, etc.) were intended, more context is needed. But for the common calculus task of differentiation, the derivative is \( \boldsymbol{2x} \).