Question

（部分题目）
$\frac{9}{14} + \frac{3}{14}$
$\frac{9}{14} + \frac{1}{4} = \frac{9}{14} + \frac{}{14}$
$\frac{11}{14} + \frac{3}{14}$
$\frac{11}{14} + \frac{1}{7} = \frac{11}{14} + \frac{}{14}$
$\frac{1}{7} + \frac{6}{14} = \frac{}{14} + \frac{6}{14}$
$\frac{7}{10} + \frac{3}{10}$
$\frac{7}{10} + \frac{1}{6} = \frac{7}{10} + \frac{}{10}$
$\frac{1}{3} + \frac{12}{10} = \frac{}{10} + \frac{12}{10}$
$\frac{1}{6} + \frac{4}{10}$
$\frac{4}{12} + \frac{8}{6}$
$\frac{1}{3} + \frac{3}{15}$
$\frac{2}{6} + \frac{1}{9} = \frac{}{18} + \frac{}{18}$
$\frac{1}{6} + \frac{4}{9}$
$\frac{2}{3} + \frac{3}{4}$
$\frac{1}{3} + \frac{3}{5}$
$\frac{1}{7} + \frac{1}{2}$

Explanation:

Let's take problem 35: $\boldsymbol{\frac{1}{3} + \frac{3}{15}}$ as an example to solve.

Step1: Simplify the second fraction

Simplify $\frac{3}{15}$ by dividing numerator and denominator by their greatest common divisor, which is 3. So $\frac{3\div3}{15\div3}=\frac{1}{5}$. Now the problem becomes $\frac{1}{3}+\frac{1}{5}$.

Step2: Find a common denominator

The least common denominator of 3 and 5 is 15. Rewrite each fraction with denominator 15: $\frac{1\times5}{3\times5}=\frac{5}{15}$ and $\frac{1\times3}{5\times3}=\frac{3}{15}$.

Step3: Add the fractions

Add the numerators: $\frac{5}{15}+\frac{3}{15}=\frac{5 + 3}{15}=\frac{8}{15}$.

Answer:

$\frac{8}{15}$