QUESTION IMAGE
Question
the means and mean absolute deviations of the individual times of members on two 4 x 400 - meter relay track teams are shown in the table below.
| means and mean absolute deviations of individual times of members of 4 x 400 - meter relay track teams | ||
|---|---|---|
| mean | 59.32 s | 59.1 s |
| mean absolute deviation | 1.5 s | 2.4 s |
what is the ratio of the difference in the means of the two teams to the mean absolute deviation of team b?
0.09
0.15
0.25
0.65
Step1: Calculate difference in means
$|59.32 - 59.1|= 0.22$
Step2: Calculate the ratio
$\frac{0.22}{2.4}\approx0.09$
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0.09