Question

monday:
$\frac{3}{7}+\frac{1}{2}=$
$\frac{1}{2}-\frac{3}{10}=$
$\frac{2}{3}$ of $12=$
$5\frac{3}{4}+6\frac{5}{6}=$
$4\frac{7}{8}-1\frac{4}{5}=$
$\frac{1}{6}\times6=$
tuesday:
$\frac{1}{4}+\frac{9}{12}=$
$\frac{1}{2}-\frac{3}{8}=$
$\frac{3}{4}$ of $8=$
$4\frac{1}{5}+5\frac{1}{2}=$
$7\frac{1}{4}-3\frac{2}{3}=$
$2\times\frac{4}{5}=$
wednesday:
$\frac{4}{8}+\frac{1}{3}=$
$\frac{3}{4}-\frac{1}{3}=$
$\frac{2}{5}$ of $10=$
$3\frac{5}{6}+4\frac{1}{2}=$
$8\frac{2}{5}-4\frac{3}{4}=$
$6\times\frac{3}{8}=$

Explanation:

Step1: Solve Monday's first problem

Find common denominator for $\frac{3}{7}+\frac{1}{2}$.
$\frac{3}{7}+\frac{1}{2}=\frac{6}{14}+\frac{7}{14}=\frac{13}{14}=1\frac{3}{14}$

Step2: Solve Monday's second problem

Find common denominator for $\frac{1}{2}-\frac{2}{10}$.
$\frac{1}{2}-\frac{2}{10}=\frac{5}{10}-\frac{2}{10}=\frac{3}{10}$

Step3: Solve Monday's third problem

Calculate $\frac{2}{3}$ of 12.
$\frac{2}{3} \times 12 = 8$

Step4: Solve Monday's fourth problem

Add mixed numbers $5\frac{3}{4}+6\frac{5}{6}$.
$5\frac{3}{4}+6\frac{5}{6}=5\frac{9}{12}+6\frac{10}{12}=11\frac{19}{12}=12\frac{7}{12}$

Step5: Solve Monday's fifth problem

Subtract mixed numbers $4\frac{7}{8}-1\frac{4}{5}$.
$4\frac{7}{8}-1\frac{4}{5}=4\frac{35}{40}-1\frac{32}{40}=3\frac{3}{40}$

Step6: Solve Monday's sixth problem

Calculate $\frac{1}{6} \times 6$.
$\frac{1}{6} \times 6 = 1$

Step7: Solve Tuesday's first problem

Add fractions $\frac{1}{4}+\frac{9}{12}$.
$\frac{1}{4}+\frac{9}{12}=\frac{3}{12}+\frac{9}{12}=\frac{12}{12}=1$

Step8: Solve Tuesday's second problem

Find common denominator for $\frac{1}{2}-\frac{2}{6}$.
$\frac{1}{2}-\frac{2}{6}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}$

Step9: Solve Tuesday's third problem

Calculate $\frac{3}{4}$ of 8.
$\frac{3}{4} \times 8 = 6$

Step10: Solve Tuesday's fourth problem

Add mixed numbers $4\frac{1}{5}+5\frac{1}{2}$.
$4\frac{1}{5}+5\frac{1}{2}=4\frac{2}{10}+5\frac{5}{10}=9\frac{7}{10}$

Step11: Solve Tuesday's fifth problem

Subtract mixed numbers $7\frac{1}{4}-3\frac{2}{3}$.
$7\frac{1}{4}-3\frac{2}{3}=7\frac{3}{12}-3\frac{8}{12}=6\frac{15}{12}-3\frac{8}{12}=3\frac{7}{12}$

Step12: Solve Tuesday's sixth problem

Calculate $2 \times \frac{4}{5}$.
$2 \times \frac{4}{5}=\frac{8}{5}=1\frac{3}{5}$

Step13: Solve Wednesday's first problem

Find common denominator for $\frac{3}{6}+\frac{1}{3}$.
$\frac{3}{6}+\frac{1}{3}=\frac{3}{6}+\frac{2}{6}=\frac{5}{6}$

Step14: Solve Wednesday's second problem

Find common denominator for $\frac{2}{4}-\frac{1}{3}$.
$\frac{2}{4}-\frac{1}{3}=\frac{1}{2}-\frac{1}{3}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}$

Step15: Solve Wednesday's third problem

Calculate $\frac{2}{5}$ of 10.
$\frac{2}{5} \times 10 = 4$

Step16: Solve Wednesday's fourth problem

Add mixed numbers $3\frac{5}{6}+4\frac{1}{2}$.
$3\frac{5}{6}+4\frac{1}{2}=3\frac{5}{6}+4\frac{3}{6}=7\frac{8}{6}=8\frac{1}{3}$

Step17: Solve Wednesday's fifth problem

Subtract mixed numbers $8\frac{2}{5}-4\frac{1}{4}$.
$8\frac{2}{5}-4\frac{1}{4}=8\frac{8}{20}-4\frac{5}{20}=4\frac{3}{20}$

Step18: Solve Wednesday's sixth problem

Calculate $6 \times \frac{3}{8}$.
$6 \times \frac{3}{8}=\frac{18}{8}=\frac{9}{4}=2\frac{1}{4}$

Answer:

Monday	Tuesday	Wednesday
$\frac{3}{10}$	$\frac{1}{6}$	$\frac{1}{6}$
$8$	$6$	$4$
$12\frac{7}{12}$	$9\frac{7}{10}$	$8\frac{1}{3}$
$3\frac{3}{40}$	$3\frac{7}{12}$	$4\frac{3}{20}$
$1$	$1\frac{3}{5}$	$2\frac{1}{4}$