Question

5 multiple choice 1 point which of the following statements best explains why a paper disc containing catalase enzyme rises in a solution of hydrogen peroxide? the hydrogen peroxide degrades the paper disc material, causing it to be lighter. water molecules are produced, which are lighter than hydrogen peroxide, causing the disc to become buoyant oxygen bubbles are produced and are trapped under the paper disc, causing it to become buoyant 6 multiple answer 1 point you have placed a disc containing catalase into a solution of 10% h2o2. it takes 5 seconds to rise to the top. when you place a disc containing catalase into 20% h2o2. it also takes 5 seconds to rise to the top. why doesnt the disk rise faster? (check all that apply) all enzyme active sites are occupied the enzyme has reached its maximum velocity (vmax) the hydrogen peroxide concentration is so high that the catalase enzyme is denaturing 7 multiple choice 1 point in order for a chemical reaction to occur, an input of energy is required, which is referred to as the activation energy enzyme product active site

Explanation:

Question 5:

Catalase enzyme catalyzes the decomposition of hydrogen peroxide into water and oxygen. The oxygen bubbles produced get trapped under the paper - disc, making it buoyant.

Question 6:

When all enzyme active sites are occupied, the reaction rate cannot increase further as there are no free sites for more substrate (hydrogen peroxide) to bind. This also means the enzyme has reached its maximum velocity (Vmax). High hydrogen peroxide concentration doesn't necessarily mean denaturation in this context as the disc still rises in both cases.

Question 7:

The energy input required for a chemical reaction to occur is called activation energy. Enzymes lower this activation energy, products are the results of the reaction, and the active - site is where the substrate binds to the enzyme.

Answer:

Question 5: Oxygen bubbles are produced and are trapped under the paper disc, causing it to become buoyant

Question 6: All enzyme active sites are occupied, The enzyme has reached its maximum velocity (Vmax)

Question 7: activation energy