Question

c) and d) are mutually exclusive events. find p(c or d)
p(c) = \frac{2}{7}, p(d) = \frac{4}{7}
(i) p(c or d) = \square
(round to three decimal places as needed)

Explanation:

Step1: Recall mutually exclusive formula

For mutually exclusive events, $P(C \text{ or } D) = P(C) + P(D)$

Step2: Substitute given probabilities

$P(C) = \frac{2}{7}$, $P(D) = \frac{4}{7}$
$P(C \text{ or } D) = \frac{2}{7} + \frac{4}{7}$

Step3: Calculate sum and simplify

$P(C \text{ or } D) = \frac{6}{7} \approx 0.857$

Answer:

$0.857$