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name: perform the following calculations—must show work for credit: 1. …

Question

name:
perform the following calculations—must show work for credit:

  1. a photon of light has a frequency of 2.68 x 10^6 hz. calculate its energy & identify the type of radiation.

e = h·v
e=(6.626 x 10^(-34) j·s)(2.68 x 10^6 s^(-1))=

  1. calculate the frequency and energy of blue light with a wavelength of 4.00 x 10^(-7) m.

3.00 x 10^8 m/s=(4.00 x 10^(-7) m)(v)
e=(6.626 x 10^(-34) j·s)( )
e=

Explanation:

Step1: Recall Planck - Einstein relation for photon energy

The energy of a photon is given by $E = h
u$, where $h = 6.626\times10^{-34}\ J\cdot s$ (Planck's constant) and $
u$ is the frequency of the photon.

Step2: Calculate energy for the first photon

Given $
u_1=2.68\times 10^{6}\ Hz$, then $E_1=h
u_1=(6.626\times 10^{-34}\ J\cdot s)\times(2.68\times 10^{6}\ s^{-1})$.
\[

$$\begin{align*} E_1&=(6.626\times2.68)\times10^{-34 + 6}\ J\\ &=17.75768\times10^{-28}\ J\\ &\approx1.78\times 10^{-27}\ J \end{align*}$$

\]
This frequency corresponds to radio - wave radiation (since radio - wave frequencies are in the range of $3\ Hz$ to $300\ GHz$ and $2.68\times 10^{6}\ Hz$ is in this range).

Step3: Calculate frequency of blue light

We know that the speed of light $c = 3.00\times 10^{8}\ m/s$, and the relation $c=\lambda
u$. Given $\lambda = 4.00\times 10^{-7}\ m$, then $
u_2=\frac{c}{\lambda}=\frac{3.00\times 10^{8}\ m/s}{4.00\times 10^{-7}\ m}=7.50\times 10^{14}\ Hz$.

Step4: Calculate energy of blue light

Using $E = h
u$, with $h = 6.626\times 10^{-34}\ J\cdot s$ and $
u_2 = 7.50\times 10^{14}\ Hz$, we have $E_2=h
u_2=(6.626\times 10^{-34}\ J\cdot s)\times(7.50\times 10^{14}\ s^{-1})$.
\[

$$\begin{align*} E_2&=(6.626\times7.50)\times10^{-34 + 14}\ J\\ &=49.695\times10^{-20}\ J\\ &\approx4.97\times 10^{-19}\ J \end{align*}$$

\]
This frequency and energy correspond to visible light (blue light is part of the visible - light spectrum which has frequencies in the range of approximately $4.0\times 10^{14}\ Hz$ to $7.5\times 10^{14}\ Hz$).

Answer:

  1. Energy of the first photon: $E_1\approx1.78\times 10^{-27}\ J$, type of radiation: radio - wave.
  2. Frequency of blue light: $

u_2 = 7.50\times 10^{14}\ Hz$, energy of blue light: $E_2\approx4.97\times 10^{-19}\ J$