QUESTION IMAGE
Question
name:
perform the following calculations—must show work for credit:
- a photon of light has a frequency of 2.68 x 10^6 hz. calculate its energy & identify the type of radiation.
e = h·v
e=(6.626 x 10^(-34) j·s)(2.68 x 10^6 s^(-1))=
- calculate the frequency and energy of blue light with a wavelength of 4.00 x 10^(-7) m.
3.00 x 10^8 m/s=(4.00 x 10^(-7) m)(v)
e=(6.626 x 10^(-34) j·s)( )
e=
Step1: Recall Planck - Einstein relation for photon energy
The energy of a photon is given by $E = h
u$, where $h = 6.626\times10^{-34}\ J\cdot s$ (Planck's constant) and $
u$ is the frequency of the photon.
Step2: Calculate energy for the first photon
Given $
u_1=2.68\times 10^{6}\ Hz$, then $E_1=h
u_1=(6.626\times 10^{-34}\ J\cdot s)\times(2.68\times 10^{6}\ s^{-1})$.
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This frequency corresponds to radio - wave radiation (since radio - wave frequencies are in the range of $3\ Hz$ to $300\ GHz$ and $2.68\times 10^{6}\ Hz$ is in this range).
Step3: Calculate frequency of blue light
We know that the speed of light $c = 3.00\times 10^{8}\ m/s$, and the relation $c=\lambda
u$. Given $\lambda = 4.00\times 10^{-7}\ m$, then $
u_2=\frac{c}{\lambda}=\frac{3.00\times 10^{8}\ m/s}{4.00\times 10^{-7}\ m}=7.50\times 10^{14}\ Hz$.
Step4: Calculate energy of blue light
Using $E = h
u$, with $h = 6.626\times 10^{-34}\ J\cdot s$ and $
u_2 = 7.50\times 10^{14}\ Hz$, we have $E_2=h
u_2=(6.626\times 10^{-34}\ J\cdot s)\times(7.50\times 10^{14}\ s^{-1})$.
\[
\]
This frequency and energy correspond to visible light (blue light is part of the visible - light spectrum which has frequencies in the range of approximately $4.0\times 10^{14}\ Hz$ to $7.5\times 10^{14}\ Hz$).
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- Energy of the first photon: $E_1\approx1.78\times 10^{-27}\ J$, type of radiation: radio - wave.
- Frequency of blue light: $
u_2 = 7.50\times 10^{14}\ Hz$, energy of blue light: $E_2\approx4.97\times 10^{-19}\ J$