Question

one candy is drawn and replaced from the bag 200 times. how many times would you expect to draw a green candy? ? times

Explanation:

Step1: Calculate the probability of drawing a green candy

The total number of candies is $10 + 6+4=20$. The number of green candies is 10. So the probability $P$ of drawing a green candy is $P=\frac{10}{20}=\frac{1}{2}$.

Step2: Calculate the expected number of times

The number of trials $n = 200$. The expected - value formula is $E=n\times P$. Substitute $n = 200$ and $P=\frac{1}{2}$ into the formula, we get $E = 200\times\frac{1}{2}=100$.

Answer:

100