Question

a phlebotomist draws the blood of a random sample of 50 patients and determines their blood types as shown. complete parts (a) and (b).
o a a a o
b o b a o
ab b a b ab
o o a a o
ab o a b a
o a a o a
o a o b o
o ab a a o
o a o o o
o a o a o
(a) draw a frequency bar graph.
choose the correct graph below.
a. bar graph with a, ab, b, o
b. bar graph
c. bar graph
d. bar graph

Explanation:

Step1: Count frequency of each blood type

• Blood type A: Let's count. Looking at the list:

Row 1: A, A, A (wait, no, let's list each:
First column (O): O, B, AB, O, AB, O, O, O, O, O → count O: let's see, first column: O (1), B (2), AB (3), O (4), AB (5), O (6), O (7), O (8), O (9), O (10) → O: 10? Wait no, let's do each blood type:

Blood type A: Let's go through each entry:

First row: O, A, A, A, O → A: 3
Second row: B, O, B, A, O → A: 1 (total 4)
Third row: AB, B, A, B, AB → A: 1 (total 5)
Fourth row: O, O, A, A, O → A: 2 (total 7)
Fifth row: AB, O, A, B, A → A: 2 (total 9)
Sixth row: O, A, A, O, A → A: 3 (total 12)
Seventh row: O, A, O, B, A → A: 2 (total 14)
Eighth row: O, AB, A, O, O → A: 1 (total 15)
Ninth row: O, A, O, O, A → A: 2 (total 17)
Tenth row: O, A, O, A, O → A: 2 (total 19)? Wait, maybe better to count all A's:

Looking at the data:

Column 2 (A): A, O, B, O, O, A, A, A, AB, A, A → Wait, maybe a better way: let's list all 50 entries.

Wait, the data is:

Row 1: O, A, A, A, O (5)
Row 2: B, O, B, A, O (5)
Row 3: AB, B, A, B, AB (5)
Row 4: O, O, A, A, O (5)
Row 5: AB, O, A, B, A (5)
Row 6: O, A, A, O, A (5)
Row 7: O, A, O, B, A (5)
Row 8: O, AB, A, O, O (5)
Row 9: O, A, O, O, A (5)
Row 10: O, A, O, A, O (5)

Now count A's:

Row 1: 3 (A, A, A)
Row 2: 1 (A)
Row 3: 1 (A)
Row 4: 2 (A, A)
Row 5: 2 (A, A)
Row 6: 3 (A, A, A)
Row 7: 2 (A, A)
Row 8: 1 (A)
Row 9: 2 (A, A)
Row 10: 2 (A, A)

Now sum: 3+1=4; +1=5; +2=7; +2=9; +3=12; +2=14; +1=15; +2=17; +2=19. Wait, but total patients are 50. Let's check O:

Row 1: 2 (O, O)
Row 2: 2 (O, O)
Row 3: 0
Row 4: 3 (O, O, O)
Row 5: 1 (O)
Row 6: 2 (O, O)
Row 7: 2 (O, O)
Row 8: 3 (O, O, O)
Row 9: 3 (O, O, O)
Row 10: 3 (O, O, O)

Sum O: 2+2=4; +3=7; +1=8; +2=10; +2=12; +3=15; +3=18; +3=21. Wait, maybe I'm miscounting. Alternatively, let's use a better approach:

List all blood types:

O: Let's count each O:

First column (O): O (1), B (2), AB (3), O (4), AB (5), O (6), O (7), O (8), O (9), O (10) → 1 (row1) + 0 (row2) + 0 (row3) + 1 (row4) + 0 (row5) + 1 (row6) + 1 (row7) + 1 (row8) + 1 (row9) + 1 (row10) → Wait, no, each row has 5 entries. Let's index each entry:

Entries:

1: O

2: A

3: A

4: A

5: O

6: B

7: O

8: B

9: A

10: O

11: AB

12: B

13: A

14: B

15: AB

16: O

17: O

18: A

19: A

20: O

21: AB

22: O

23: A

24: B

25: A

26: O

27: A

28: A

29: O

30: A

31: O

32: A

33: O

34: B

35: A

36: O

37: AB

38: A

39: O

40: O

41: O

42: A

43: O

44: O

45: A

46: O

47: A

48: O

49: A

50: O

Now count each blood type:

A: entries 2,3,4,9,13,18,19,23,25,27,28,30,32,35,38,42,45,47,49 → let's count: 2 (1),3(2),4(3),9(4),13(5),18(6),19(7),23(8),25(9),27(10),28(11),30(12),32(13),35(14),38(15),42(16),45(17),47(18),49(19). So A:19

B: entries 6,8,12,14,24,34 → 6(1),8(2),12(3),14(4),24(5),34(6). So B:6

AB: entries 11,15,21,37 → 11(1),15(2),21(3),37(4). So AB:4

O: total 50 - 19 -6 -4 = 21. Let's check: entries 1,5,7,10,16,17,20,22,26,29,31,33,36,39,40,41,43,44,46,48,50 → 21. Yes.

So frequencies:

A:19, B:6, AB:4, O:21

Now check the graphs:

Graph A: A (blue) ~20, AB (red) ~5, B (green) ~5, O (yellow) ~20. Wait, our counts: A:19, O:21, AB:4, B:6. So A (19) close to 20, O (21) close to 20, AB (4) small, B (6) small. Let's check the options:

Option A: A (blue) ~20, AB (red) ~5, B (green) ~5, O (yellow) ~20. Our A:19, O:21, AB:4, B:6. So A's bar ~20, O's bar ~20, AB ~4 (small), B ~6 (small). That matches.

Option B: O's bar is small, but we have O:21, so B is wrong.

Option C: A's bar is small, wrong.

Option D: Incomplete, wrong.

So the correct graph is A.

Answer:

A. (the graph with A ~20, AB ~5, B ~5, O ~20)