Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

pink body = tt, tt yellow body = tt4. spongebob squarepants recently me…

Question

pink body = tt, tt yellow body = tt4. spongebob squarepants recently met spongesusie roundpants at a dance. spongebob is heterozygous for his square shape, but spongesusie is round. create a punnett square to show the possibilities that would result if spongebob and spongesusie had children. hint: read question #2!a. list the possible genotypes and phenotypes for their children.b. what are the chances of a child with a square shape? __ out of or %c. what are the chances of a child with a round shape? out of or %5. patrick met patti at the dance. both of them are heterozygous for their pink body color, which is dominant over a yellow body color. create a punnett square to show the possibilities that would result if patrick and patti had children. hint: read question #3!a. list the possible genotypes and phenotypes for their children.b. what are the chances of a child with a pink body? out of or %c. what are the chances of a child with a yellow body? out of or __%

Explanation:

Step1: Define genotypes (Problem 4)

SpongeBob: $Ss$ (heterozygous square), SpongeSusie: $ss$ (round)

Step2: Build Punnett Square (Problem 4)

$$\begin{array}{|c|c|} \hline S & s \\ \hline Ss & ss \\ \hline Ss & ss \\ \hline \end{array}$$

Step3: List genotypes/phenotypes (4A)

Genotypes: $Ss$, $ss$; Phenotypes: Square body, Round body

Step4: Calculate square shape chance (4B)

Count $Ss$: 2 out of 4. $\frac{2}{4} = 50\%$

Step5: Calculate round shape chance (4C)

Count $ss$: 2 out of 4. $\frac{2}{4} = 50\%$

Step6: Define genotypes (Problem 5)

Patrick: $Tt$ (heterozygous pink), Patti: $Tt$ (heterozygous pink)

Step7: Build Punnett Square (Problem 5)

$$\begin{array}{|c|c|} \hline T & t \\ \hline TT & Tt \\ \hline Tt & tt \\ \hline \end{array}$$

Step8: List genotypes/phenotypes (5A)

Genotypes: $TT$, $Tt$, $tt$; Phenotypes: Pink body, Yellow body

Step9: Calculate pink body chance (5B)

Count $TT+Tt$: 3 out of 4. $\frac{3}{4} = 75\%$

Step10: Calculate yellow body chance (5C)

Count $tt$: 1 out of 4. $\frac{1}{4} = 25\%$

Answer:

Problem 4

A. Genotypes: $Ss$, $ss$; Phenotypes: Square body, Round body
B. 2 out of 4 or 50%
C. 2 out of 4 or 50%

Problem 5

A. Genotypes: $TT$, $Tt$, $tt$; Phenotypes: Pink body, Yellow body
B. 3 out of 4 or 75%
C. 1 out of 4 or 25%