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practice problems: answer the questions below given each situation and …

Question

practice problems: answer the questions below given each situation and the data collected.
1 there are 150 residents at the local senior citizen assisted living home. sixty names were drawn at random and those residents were asked to list their favorite breakfast item available at the cafeteria. the results of the 60-person sample are shown below. assuming the sample is valid and represents the population of the assisted living home, fill in the table with the inferences about the population: (1) population: the number of total residents that would most likely have chosen that breakfast item had each resident been polled; and (2) percentage %: the percentage of the population this number represents.

breakfastsamplepopulation%
oatmeal205033.33%
protein shake97.515%
pancakes/waffles123020%
toast + yogurt4106.67

hint:
population: set up a key!
$\frac{survey part}{survey total}=\frac{x}{total population}$
percent:
$\frac{survey part}{survey total} \times 100 = \\%$

Explanation:

Step1: Verify Eggs + Bacon values

Population calculation:

$\frac{15}{60} \times 150 = 37.5$

Percentage calculation:

$\frac{15}{60} \times 100 = 25\%$

Step2: Verify Oatmeal values

Population calculation:

$\frac{20}{60} \times 150 = 50$

Percentage calculation:

$\frac{20}{60} \times 100 \approx 33.33\%$

Step3: Verify Protein Shake values

Population calculation:

$\frac{9}{60} \times 150 = 22.5$

Percentage calculation:

$\frac{9}{60} \times 100 = 15\%$

Step4: Verify Pancakes/Waffles values

Population calculation:

$\frac{12}{60} \times 150 = 30$

Percentage calculation:

$\frac{12}{60} \times 100 = 20\%$

Step5: Verify Toast + Yogurt values

Population calculation:

$\frac{4}{60} \times 150 = 10$

Percentage calculation:

$\frac{4}{60} \times 100 \approx 6.67\%$

Answer:

BreakfastSamplePopulation%
Oatmeal205033.33%
Protein Shake922.515%
Pancakes/Waffles123020%
Toast + Yogurt4106.67%

Note: The original Protein Shake population value (7.5) was incorrect; the corrected value is 22.5. All other values were already accurate.