Question

problem 1:
parents: pea plants with yellow seeds (heterozygous) crossed with pea plants with green seeds (homozygous recessive).
create a punnett square and determine the possible genotypes of the offspring.
what are the phenotypes and percentage chance of each phenotype?
genotypes\tdd\tdd\tdd
phenotypes\t\t\t
percentage chance\t\t\t

Explanation:

Step1: Fill Punnett square

Parent 1 (heterozygous yellow): $D,d$; Parent 2 (homozygous green): $d,d$

	$D$	$d$
$d$	$Dd$	$dd$

Step2: Identify offspring genotypes

From the Punnett square, the only possible genotypes are $Dd$ and $dd$. $DD$ is not possible.

Step3: Assign phenotypes

Yellow seeds are dominant ($D_-$), green are recessive ($dd$). So:

• $Dd$: Yellow seeds
• $dd$: Green seeds

Step4: Calculate percentage chance

Total offspring squares = 4

• $Dd$ count = 2, percentage: $\frac{2}{4} \times 100\% = 50\%$
• $dd$ count = 2, percentage: $\frac{2}{4} \times 100\% = 50\%$
• $DD$ count = 0, percentage: $0\%$

Answer:

Completed Punnett Square:

	$D$	$d$
$d$	$Dd$	$dd$

Completed Table:

Genotypes	DD	Dd	dd
Percentage Chance	0%	50%	50%

Final Summary:

• Possible offspring genotypes: $Dd$ and $dd$
• Phenotypes & percentages: Yellow seeds (50%), Green seeds (50%)